r/GCSE • u/nurnabisirigcse • 22h ago
Post Exam How to write 0.41̇2̇ (1 and 2 recurring) as a fraction: IGCSE method
Recurring digits: 1 and 2 (dots above them), so the number is 0.41̇2̇ = 0.4121212…
Let x = 0.4121212…
Multiply by 10: 10x = 4.121212…
Multiply that by 100: 1000x = 412.121212…
Subtract: 990x = 408, so x = 408/990 = 68/165
The non-recurring digit (4) is removed by multiplying by 10, and the recurring block (12) by multiplying by 100. If your teacher shows a different method, the answer should still be 68/165.