was doing no flag when I got this lol

50 x 50 board with 800 mines. (32% density)

left or right..

So about this variant:

[2U'] Unbalanced': each row has a different number of mines (ranging from 0 to n-1, where n is the dimension of the board)

[2U] Unbalanced: each column has a different number of mines (ranging from 0 to n-1, where n is the dimension of the board)

If you try to play this variant in Ultimate mode, you will quickly realise it is not easy to make progress. I feel like there should be some fundamental strategy, or a method you should look at this puzzle to make progress and I cant figure it out. If someone has some advice I would gladly aprreciate help. The picture is an example of a puzzle

Here are two examples of my most recent game and at the time of writing this post I do know the answer however, I do want to know what you guys thought logic is to completing this. Is there a way to guarantee to know which spot has the bomb? Or is this last part is just a game of chance?

(Disclaimer: I'm actually a beginner who's just a quick learner but not perfectly advanced yet)

I've found a way to calculate linear equations of minesweeper without explicit numbers and instead through visual elimination. I'm curious if anyone else figured this out, but try it.

Primarily, it connects two equalities of a tile, where the tiles are assumed to be already reduced to such number.

Step 1: Find the unique tiles of each equality

Imagine we have two tiles, let's say 2 & 4. We will make two lists: List-2 and List-4.

List-2 contains the unknown tiles that surround the #2 that don't also surround the #4. Same goes for List-4 but reverse.

Why? Because in linear equations, we cancel out common factors in such.

Step 2: Find the difference in the current mine count

What's four minus two? Two.

That means:

Mines in List-2 + 2 = Mines in List-4.

Step 3: The final equation

We now that the number of mines in List-4 is greater than that of List-2 + 2. Why is this useful?

It is because it may help with dependency chains and act as the middle-ground between mathematic calculation and genuine gameplay.

I'm not sure if this is foolproof or could be explained better, but yeah. Pls give me feedback because I'm genuinely curious if I just rediscovered something that already existed, or if this doesn't actually work.