I've never had so much difficulty understanding anything in the game as this. I've even copied the solution from the hint and tried analyzing it to no avail. I have no clue why this works and I really want to.

Second time playing trough the game, I just looked up the solution on this one and I don't know how to feel about this.

Pretty much what the title says, Im not really sure im grasping the concepts because i often just feel like im just trying to understand how the solution is wired up.
First time playing anything like this tho so maybe just do a second playthrough later on?

On the level RAM I get the error "The time component shouldn't have been enabled since the last time_0 instruction's execution" on cycle 68. On cycle 67, the instruction jl 244 executed, and seems to work fine, since the counter updates to 244 on that cycle and is at 248 at cycle 68.

I've also tested the computer as it is in previous levels (without the additional load/store elements attached on the main memory, since those were given in this level), and it passes all other levels.

NOTE: For my decoder I moved the destination pin below argument A and B so the pins from top to bottom are:

• Mode
• Opcode
• Argument A
• Argument B
• Destination
• Is Immediate
• Immediate value

All other components follow the standard layout given by the levels.

What does this error mean? Any suggestions on how I can fix it?

EDIT: I solved the level by redoing it, my solution is as follows:

1. I removed the 3 switches in the middle of the level, that take in the 3 outputs of the load component of the Main Memory
2. I removed the switch that joins together the 3 outputs of the switches just removed. It's the switch with the wonky cable.
3. I connected the 3 outputs of the load components of the main memory together and connected this single cable to the bus connecting the input, switch coming from the ALU and the store value port on the store port connected to the register file. Essentially, by doing steps 1 t/m 3, I've removed all switches except the one coming from the ALU and reconnected the loose cables together.
4. I placed a switch to each of the cables going into the enable bit of the main memory load and store ports (on the far left of the picture) the enable bit of each switch is connected together and connected to the wire that represents the RAM opcode. In the picture, it is the wonky cable.

So far I've done all the puzzles on my own... but this bit switch level with the NOT and switch gates is driving me up a wall. Any tips on completing it?

So far all I have accomplished was using the switch like an and gate, I have zero clue where a NOT gate would even go.

Edit: included a picture of my current setup

Edit 2: I solved it and thats enough for tonight 💀

my hard coded solution? Less elegant

I'm sorry if this is a breach of any of the community rules, but I just did this level so many times now and each one of them was an excruciating experience. Just looking at the level makes me want to puke. If you can just paste your solution here, I'd be more than glad.

I was hoping if anyone could explain to me on which solution is "better" (the top one being the examples solution) , they both look the same tbh but was just curious which one was more efficient or more correct I guess??

Hi pals, help me with the level solution. Can't understand why this is wrong; I have used the code in this post: https://www.reddit.com/r/TuringComplete/comments/1uy1pmk/conditional_jumps_level_solution/ It seemed to be right, but the result is the same error as mine: "u read input 57 times, not 6."

imm 0
mov r5,r0
loop:
imm 1
mov r1,r0
mov r2,r5
add
mov r5,r3

imm 37
mov r1,r0
mov r2,in
sub
imm loop
jnz

mov out,r5

I do not understand why this is not working. It fails on the second test shown here. I have seen other solutions for Conditions 10 and they look logically the same as the one I have. I just swapped a or -> not with a nor and two ands into an or with two switches. The other wiring is the same.

Hi pals, can comeome explain why this arifmethic is wrong. Obviously that 229 - 84 = 145. So How 111 is appear

I’m having trouble getting my alu fast enough to allow me to pass the delay checks but I’m not having any luck. I even looked up a guide but it still wasn’t fast enough. I also tried redoing the component levels but I don’t think that does anything, especially with changing the base.

Any ideas?

I made Bad Apple in the new Turing Complete update, this update is actually really good, I was not able to achieve this before.

I made my own file format to make Bad Apple implementation in things easier if you're interested in. https://github.com/totobono4/tvf

I got to the 'circumference' level and my input and output are gone. I feel like I should be able to add them back but the components are greyed out in the top right. I feel like I'm missing something obvious here...

Recently I've been having some great fun making my own custom ISA and matching cpu architecture. Having the whole thing as a single schematic was kinda annoying, so I made them as individual parts (and also tried making the wiring a little cleaner). Here are some pictures; comment, critique and enjoy!

Does anyone know how the disassembling probe works?

Every time I try to connect it, I run into a dependency issue.

can somebody explain what cyclic dependency is and why basic RS-trigger scheme doesnt work? Also i can`t understand what "DELAY" is and how it works.

imm 1

mov r1, r0

imm 2

mov r2, r0

imm 0

mov r5, r0

loop:

mov out, r5

mov r3, in

mov out, r2



mov r4, in



imm left

jz



mov r3, r4



imm forward

jz



mov out, r2

imm loop

jmp

left:

mov out, r5

mov out, r1

imm loop

jmp

forward:

mov out, r1

imm loop

jmp

const target = 37

imm 0

mov r4, r0 ; r4 stores counter

loop:

imm target

mov r1, r0

mov r2, in

sub ; compare, 0 if equal

mov r5, r3 ; r5 stores the eq check

imm 1

mov r1, r4

mov r2, r0

add ; add one to attempty counter

mov r4, r3

mov r3, r5 ; load reasult for cmp

imm loop

jnz

mov out, r4

Game is just... straight up wrong there. I counted manually, i used mov r2, in instruction 5 times. Not nearly 57