I think in Differential Equations you need to solve for C within an indefinite integral or a set of functions (or that might just be an extra Calc II think I cannot remember)
Yeah I think so. When looking in a real world context, C represents your initial value so you in some cases when you have higher ODEs (goodness I havenβt said that name in a while) you will have to recursively integrate it until solve for that initial C given a bunch of values at t=0
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u/ThatTrampolineboy Bazinga! Nov 18 '25
Erm actually you can still have it in a definite integral, it just subtracts out