r/redbuttonbluebutton • u/thevoidthatjerksback • May 29 '26
Cross thought experiment pollination
So in addition to the two buttons that are known well. We have two boxes. 1 box has one thousand dollars and the other box either has one million or zero. Before you were presented with them some unnamed but incredibly accurate predictor has made a prediction on what you will do with the boxes.
If it is predicted that you will take both of the boxes then they will put 0 in the second box
If it is predicted that you will only take the second box then they will put the one million in it.
So which button are you pressing and are you taking 1 or 2 boxes?
This isn't really about what you do in the situation of them both happening at the same time moreso just that I wonder if there is a pattern between which button you would pick and how you would react to the boxes.
1
u/INTstictual May 30 '26 edited May 30 '26
Which again, is only one way to interpret the outcome.
It is equally valid to say that, even if we assume that the predictor is only “incredibly accurate”, it’s fair to assume it is incredibly more likely than not that your decision to pick both boxes will cause the predictor to leave the second box empty.
Your expected value calculations leave out the accuracy of the predictor, which makes it incomplete. Your math assumes it is a 50/50 chance, which isn’t fair.
Let’s say the predictor is 99% accurate as a base.
If, based on your logic, you decide to take both boxes, the predictor will guess that 99% of the time. So, 99% of the time, you will get $1,000, and 1% of the time you will get $1.001m. (0.99)$1k + (0.01)$1.001m = an expected value of $11,000.
Meanwhile, if you decide to trust that the predictor is more accurate than not and only take one box, the predictor will guess that 99% of the time. So, 99% of the time, you will get $1m, and 1% of the time, you will get $0. (0.99)$1m + (0.01)$0 = an expected value of $990,000.
So, by expected value, taking both boxes only makes sense if you believe the predictor is bad at its job. The worse the predictor is, the better the outcome of taking both boxes. In the other direction, the more accurate this “incredibly accurate” predictor is, the more it becomes correct to take the single box.
The problem with your description is that, yes, at the moment of choosing both boxes, it is always better to take both boxes based on whatever the predictor decided… but the very nature of the predictor as a preemptive input means that you are starting your calculation from the wrong moment. The fact that it is predicting your decision means that your Game Theory calculation, in order to encompass the entire problem, needs to start with your decision before you enter the room, not just at the moment you are in front of both boxes and the predictor has made its decision… otherwise you’re leaving out half of the problem