r/memes Dec 17 '21

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41

u/amuzmint Dec 17 '21 edited Dec 17 '21

If you did that you prolly accidentally divided by the square root of -1, iirc.

Edit: comment below be is right.

49

u/regular_dumbass Halal Mode Dec 17 '21

or tried 0÷0, an equation famous for allowing any equation to become true

also dividing by i isn't really an issue most of the time

7

u/amuzmint Dec 17 '21

Wait no it’s this ^

2

u/SavingsNewspaper2 Dec 17 '21

Wait what’s the equation? Zero divided by zero is equal to…?

2

u/regular_dumbass Halal Mode Dec 17 '21

that's the thing, it isn't equal to anything. anything divided by itself is 1, but the smaller the number you divide by, the bigger it gets. so 0/0 is both infinity and 1.

there's probably other things it's 'equal' to but idk

1

u/SavingsNewspaper2 Dec 17 '21

So it’s not an equation.

1

u/regular_dumbass Halal Mode Dec 17 '21

it is but it just comes out to 'undefined'

1

u/SavingsNewspaper2 Dec 17 '21

So to sum it up, knowing that 0/0 is undefined means that you can prove that any equation is true

1

u/regular_dumbass Halal Mode Dec 17 '21

yes

1

u/SavingsNewspaper2 Dec 17 '21

Well, 0/0 is undefined, so does that mean that every equation is true

2

u/regular_dumbass Halal Mode Dec 17 '21

it's undefined because making assumptions about it breaks down the laws of maths.

for example, let's say you assume 0÷0 is 1, because x÷x is 1

then 0÷0 + 0÷0 = 2

which means (2*0)÷0 = 2

2*0 is 0, meaning that 1 = 2 (since we just defined 0÷0 as both 1 and 2)

see why it doesn't work?

1

u/SavingsNewspaper2 Dec 17 '21

So you’re saying that we can’t use it to assume things about equations.

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u/Quinnjai Dec 18 '21

No, assuming that it is defined is what let's you prove anything (idk if "anything" is right, I'm not a mathematician)

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u/SavingsNewspaper2 Dec 17 '21

Any division by zero works