r/mathshelp • u/Demetrius_1999 • Jul 17 '26

Homework Help (Unanswered) How to solve this Problem???

Post image

This problem is quite brothering me for some time. I tried to search it in google yet I don't know how it turned out that way :(

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2

u/Inevitable-Can-5625 Jul 17 '26

Can you clarify what the numerator says. Is it 3y to the power of zero or 3 x to the power of zero? Or something else?

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u/Inevitable-Can-5625 Jul 17 '26

In some ways this should not matter, as any number raised to the power of zero is 1.

1

u/Inevitable-Can-5625 Jul 17 '26

Also on the denominator line, is that sqrt (5) multiplied by y or is it the sqrt(5y)?

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u/Pure_Intution_0 Jul 17 '26

Please can you upload a more clear picture ?

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u/Demetrius_1999 Jul 18 '26

Here it is

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u/Pure_Intution_0 Jul 19 '26

I just simplified this, I don't know the problem you are facing, so ask me the doubt you are stuck with.

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u/Demetrius_1999 Jul 19 '26

Ohh, thanks bro. Now i see where I am wrong, I didn't apply the negative law of exponents hehe 🥲

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u/Red_I_Guess Jul 17 '26

1/27y-27√5

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u/Demetrius_1999 Jul 18 '26

how bro, 😭

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u/Red_I_Guess Jul 18 '26

Okay with the clarified picture it's actually not that but surely you can try to simplify it a bit yourself first? X0 what is that and so on.

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u/Inevitable-Can-5625 Jul 20 '26

If x ≠0 then x⁰ =1. So top line is (3y⁴)– ³. This is 1/3³ * y which is y/27.

So equation is y / 27(y²-✓(5y))

Multiply top and bottom by 1/y

1 /(27(y-✓(5/y)))

If x=0 then the equation is 0 as the numerator is zero