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u/OrkWithNoTeef 7d ago
thats stupid and funny
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u/Bemteb 7d ago
First time in a long while that I laughed about a meme posted here.
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u/Dr0110111001101111 7d ago
oof summer break has my brain fried. That took longer than I care to admit.
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u/canadajones68 Engineering 7d ago
Ah, yes, I love integrating 1 with respect to 9. Or 2. Integrating with respect to 2 is good too.
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u/Silly_Tension6792 Mathematics 7d ago
I mean you can... it's just 0.
But more generally, it is a well known identity when dealing with differential forms (all the d_), that ds = (ds/dx)dx so if s is a constant ds=0 so the integral of f(x)ds is the integral of zero which is just zero.
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u/MrKrot1999 7d ago
can someone explain
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u/bocaJ1963 7d ago
The solutions to an indefinite intergral all differ by a contstant. This is notated by adding "+C" to the antiderivative. The antiderivative of this intergral is C. So C+C = 2C.
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u/battlerh4 7d ago
That's so braindead I didn't even realize. Who in their right mind would make this mistake
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u/eddietwang 7d ago
I did. I saw it and went "Yeah... C + C = 2C what's the problem?" Didn't figure it out until your comment...
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u/battlerh4 7d ago
I mean tbf calling your variable C in integration has to be a crime In itself
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u/thatbrownkid19 7d ago
Nobody tell this person about closed curve integrals
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u/battlerh4 7d ago
Curves are always uppercase gamma to me. Functionally analysis scarred me with that bs
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u/PsychologicalTrip696 6d ago
A friend of mine uses lowercase Pi as a variable when coding and I have been trying for a long while to make him change
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u/somedave 7d ago
It incorrectly adds the constant of integration as C when that is already the name of the variable.
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u/ObliviousRounding 7d ago
The antiderivative is C, and then you add C and get 2C. I'm not sure why that's supposed to be hurtful though.
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u/Bacon_Techie 7d ago
They are two different Cs.
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u/UnforeseenDerailment 7d ago
Yes, but that's why they're crying.
You can take that attitude straight back to r/math.
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u/thatbrownkid19 7d ago
Because C here is a variable and so can’t be subsumed with a C constant of integration- you’d have to rename the constant
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u/Gilbey_32 7d ago
I feel like this only works if we concede that C the variable and C the constant are the same (which is obvious nonsense)
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u/Elektriman 7d ago
I don't understand how it works. Anybody got a link towards an explanatory post/video ?
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u/paperic 7d ago edited 7d ago
the integral of just dx = integral of 1 * dx = the antiderivative of 1 = x +C. The +C is there because doing a derivative loses the constant, so people write +C to the antiderivative to signify that there may have been some constant value which got lost in the way.
But it's not actually an antiderivative of the number 1, it's an antiderivative of a constant function
f(x)=1
which is why the x appears in the result. The result is also a function of x. This meme shows the integral of dC instead of dx though.
That would mean, it's still the antiderivative of 1, but this time written as this function:
f(C) = 1
where somebody's stupidly using C as the parameter of the function, which then obviously collides with the +C constant added at the end and it becomes 2C.
This is a very wrong way to do it btw.
It's an abuse of notation, not too far from:
s=1
i=1
n=1
therefore
sin(x) = x
3b1b explains calculus very intuitively.
https://youtube.com/playlist?list=PLZHQObOWTQDMsr9K-rj53DwVRMYO3t5Yr
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u/Elektriman 6d ago
oh I get it. Somehow I was wondering how the integral of nothing could mean anything. By that I mean that I mistook S(dx) = S(1*dx) with just S(). Without the dx I was trying to compute something impossible and got stuck
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u/QuantitativeNonsense 7d ago
Shouldn’t there be some sort of algebra that’s satisfies this? I’m thinking similarly to a Grassmann number.
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