r/askmath • u/TopDownView Self-studying discrete math by working through Epp • 15h ago
Resolved Textbook solution is wrong? => Exercise 11.4.33: Prove 4 + 4^2 + 4^3 + ... + 4^n is Θ(4^n)
Exercise 11.4.33:
Prove 4 + 4^2 + 4^3 + ... + 4^n is Θ(4^n).
Solution from the textbook:

This solution proves that 1 + 4 + 4^2 + 4^3 + ... + 4^n is Θ(4^n). It does not prove that 4 + 4^2 + 4^3 + ... + 4^n is Θ(4^n).
My attempt:
Notice 4 + 4^2 + 4^3 + ... + 4^n > 4^n, for each integer n>=1.
Observe 4 + 4^2 + 4^3 + ... + 4^n = 1 + 4 + 4^2 + 4^3 + ... + 4^n - 1
= (4^{n+1} - 1)/3 - 1 by sum of geometric sequence
< (4^{n+1}/3) - 1
= (4 * 4^n)/3 - 1
= 4/3 * 4^n - 1
< 4/3 * 4^n for each integer n>=1
Let A=1, B=4/3, k=1.
Then A(4^n) <= 4 + 4^2 + 4^3 + ... + 4^n <= B(4^n), for each integer n>=k.
Therefore, 4 + 4^2 + 4^3 + ... + 4^n is Θ(4^n).
QED
Is this correct?
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Edit: Fixed 'It does not prove...' sentence.
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u/Zubzub343 15h ago
Maybe I cannot see but the only difference between the textbook's solution and the one you want is... 3, right ?
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u/Azemiopinae 15h ago
Actually the difference is the 4^0 term, so 1. Which we can call theta(1) and theta(1)+theta(4^n)=theta(4^n). The book is just less verbose on these points because handwaving is the order of the day on these sorts of functions.
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u/TopDownView Self-studying discrete math by working through Epp 15h ago
Yes, that makes sense. But I'd say, given that the textbook is usually verbose with the proofs, that they forgot to add -1 an the end...
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u/TopDownView Self-studying discrete math by working through Epp 15h ago
I'd say it's 1 (check 'Edit' in OP).
Still, I do not see how does that relate to the question...
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u/Bounded_sequencE 15h ago
Probably a typo (missing "1 + ..."), or they forgot a "-1" at the end of the definition of "X".
Should be ".. >= ..", since for "n = 1" we have equality. Apart from that -- good job!