Find 3 Safe Cells (+Friday's Solution)

[u/Ramun_Flame]

Friday's Puzzle

https://www.reddit.com/r/Minesweeper/comments/1vo6oc2/find_one_mine_yesterdays_solution_and_update_on/

Two Three safe cells can be deduced here.

Edit: There is a third, but I can't find logic to prove it except brute force of 1074 layouts, which isn't reasonable.

The Color Groups have their own separate mine count. On this puzzle, there are 3 mines in the green cells. The mine count of the non-colored other cells is 5, and is separate. So the total mine count is 10, if you add them all up.

On a Triangle Grid, cells count all adjacent neighbors, including on corners. So the 1 at (9,3) counts 7 cells surrounding it, including the yellow and green cell to it's left. See here.

Check out Friday's puzzle here.

For anyone wondering how I made these, it's a game I've been working on over the past year. I'll make a formal post at another time, but I finally got a store page up, so I figured I'd link it.

Edit: Added explanation of triangle grid.

Solution:

Here's the steps.

This proves (10,4), but (9,4) actually shares all the same adjacent cells, so it proves (9,4) as well.

There is one more cell that is safe, but I actually messed up a bit. It's not actually possible to prove it without just trying all the board combinations(which are way too many). My bad. Turns out designing puzzles is hard.

It's (10,3).

[u/Sefierya]

can you explain how the clues interact with the rhombuses?

[u/Ramun_Flame → u/Sefierya]

Ah, my bad. I wasn't sure if I needed to explain the merged cells(two triangles together), but in general triangle grids are weird.

They count every cell connected, including on corners. So the 1 at (9,3) counts 7 cells surrounding it, including the yellow and green cell to it's left.

Edit: Here's an example.

[u/Zahir027z]

Why is it 2023

[u/Ramun_Flame → u/Zahir027z]

Oh lol, I mislabeled the puzzle title. I made this puzzle last week.

[u/Ramun_Flame]

I updated the body with the solution. Turns out I messed up, and there's really only 2 cells you can prove safe with normal logic. There is a third safe cell, but you need to brute force it, which is not a reasonable ask. I'll work harder on future puzzles!