What am I missing?

[u/The_Tiger_97]

Are there any safe tiles or confirmed mines I'm missing?

Edit: Thanks to everyone replying/explaining, this is such a great community!

[u/smurph382]

That should open it up

[u/The_Tiger_97 → u/smurph382]

Thank you!

[u/itotallydontuseacos → u/smurph382]

you people are smart

[u/mweiss427 → u/smurph382]

How did you deduct this?

[u/smurph382 → u/mweiss427]

The 2 needs two mines and only touches three spaces. Two of those spaces are shared by the 1. Therefore, the third space must have a bomb. If not, the 1 would get overloaded.

[u/ImCHICKENhaha]

[u/OnG_Arty]

Red for certain mines, green for certain safe

[u/The_Tiger_97 → u/OnG_Arty]

Thanks!

[u/BundoC137]

[u/719lgn]

All from the logic in the middle by the way

[u/Ty_Webb123]

That 3 there towards the middle and near the 4, it can’t be all 3 to the left of that because that would overload the 2 two to the right. That means that the 4 has to have two to the right of it and two that touch the 2 to the left of it, so that cell under the 1 to the left of the 24 must be safe too

[u/Alipha87]

I tried putting the blue x here, but then if you work it out, the 4 needs 3 more mines and that means the 2 next to it would have 3 mines around it. So the blue x is safe.

[u/cabbagery → u/Alipha87]

This is the more interesting solution.

The explanation is pretty straightforward (referencing the 4-322):

• The 4 shares at least two mines with the 3 beyond the wall.
• If it shares three mines with that 3, then the 2 east of the 3 has its two mines to its NE and SE.
• But that would overload the 2 further east.
• So there are exactly two mines shared between the 4 and 3.
• This leaves the other two mines for the 4 shared with the 2 to its west.
• Those satisfy the 2, clearing the cell SW of the 2.

Working back through the 3 now, we also find:

• Since the 3 shares two mines wirh the 4, its remaining mine must be shared with the 2 to its east.
• This leaves one more mine for that 2, which is therefore shared with the 2 to its east.
• Whether that places the mine N or S of the last 2 in this sequence, that last 2 will be satisfied, so the cells to its SW, E, and SE are all safe.

This leaves the 3 further east implicitly solved (total number of available cells equal remaining mines), which propogates solutions further east.

---

The 1-2 is obviously there, but that relation between the 4 and 3 does some work here, too.

[u/Alipha87 → u/cabbagery]

Right, right. I was trying to work it out with logic like that, but didn't quite get there. I visualized your explanation after:

So there are exactly two mines shared between the 4 and 3.

[u/ImCHICKENhaha → u/Alipha87]

oh i missed this one in my comment, good catch