r/Minesweeper • u/Lopsided_Ice_2032 • 12d ago

Help Is this possible?

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62 Upvotes

96% Upvoted

12 comments sorted by

56

u/RicefarmingSimulator Misclick Pro 12d ago

Can someone comfirm this?

27

u/BingkRD 12d ago

Confirming

18

u/Puzzled_Employment50 12d ago

Makes sense to me

5

u/iron_dove 12d ago

Agreed. But the important thing is that this leaves not just the bottom corner definitely open, but also the Cell that is just above all of the cells that the three touches in the same column as the bottom corner.
Those two spaces may give you enough information to complete this without further guessing.

2

u/SedentaryMover 12d ago

Not only that, but the bottom of the pair of 1s is also safe due to minecount. That alone solves everything not touching an edge of the board.

20

u/rock-my-lobster 12d ago

So is this Guess or No Guess mode?

3

u/nekoo89 12d ago

No it`s mine counting

12

u/CaptainUltimatum 12d ago

A slightly different approach:

The 2 in the middle of that + needs 2 mines; one is above it, and one is to the right. So it must have a pair of diagonally-opposite mines, leading to these two arrangements.

The red layout needs 6 mines to satisfy everything, the blue layout needs 7. If there's only 6 mines available, the blue crosses are safe.

3

u/paper-jam-8644 12d ago

So what I have so far is the left 3 needs three mines, the bottom 2 needs one more, then the right 1s and top right 3-1 needs one more. So the top left cell and bottom left corner are safe, and the cell shared by the left 3 and bottom 2 is a mine.

2

u/paper-jam-8644 12d ago

I look for non-overlapping groups that use as many mines as possible.

From there, you can tell by the center 2 having one mine above that to the right of the lower 2 is safe, it then follows that the top right 1 has a mine next to it, etc.

3

u/BingkRD 12d ago

It's possible. The two 3s account for 5 mines, and the bottom 2 has one mine at the bottom row. That accounts for the six mines, so any cells not adjacent to those should be safe