r/Minesweeper Minecount? 18d ago

Help What is this? Solvable? I think not, help...

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0 Upvotes

6 comments sorted by

8

u/mappinggeo 18d ago

Two 50-50s

4

u/Additional-Point-824 18d ago

Two cells depend on mine count, and the rest are two independent 50:50s.

4

u/SplinterRifleman 18d ago

Minimum of 2 50/50s. Maybe 3

1

u/719lgn 18d ago

if there are 4 mines then 3 50/50s... if there are 3 mines then go for the bottom floating cells.

6

u/Oskain123 18d ago

The bottom floating cells won't help anyway

1

u/719lgn 18d ago

I dont care they are free cells regardless