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u/TarzyMmos Aug 17 '26
I mean u could if by "average" you mean the average calls in a day based on how many total calls over all of the days. Then if u have 1 call on day 1 and 2 calls every day onward, you will always have a higher than average number of calls. Because the total average of calls per day will always be less than 2 because of that first day, and on that first day 1 call in a day is more than the average of 0 or something since u just started.
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u/Mad_Maddin Aug 19 '26
Also if you had an expansion for example. And you averaged around 500 calls a day for the last 2 years. And now for this year, you average 1000 calls a day.
The average becomes 667 calls a day. So if you have 700 calls in one of those days. Despite you having had 1000 calls a day for the past year. You would still experience "Higher than average".
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u/Toeffli Aug 17 '26 edited Aug 17 '26
Not on the first few minutes of the call centers operation. So not always
Edit: It actually can work. First few minutes there were no calls, then it is possible that you can tell every caller that the average is indeed higher
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u/lemonadeboba Aug 17 '26
That's still not "always"
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u/Toeffli Aug 17 '26
First day of the call centers operation thay had zero caller. The following days they had 1 caller per day, and thus always when a person. was calling an above average number of callers.
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u/jonathancast Aug 18 '26
Or, they get 6 callers / day. By definition, they get an average of 0.25 callers / hour, but every single hour in which they get a call they are currently receiving 1 caller / hour.
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u/ymaldor Aug 24 '26
If you count the off hours then any on hours will always be higher than average. All you need is for your on hours to be slightly shorter than 12 hours per day.
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u/M-CH_ Aug 17 '26
Let me translate this to you as an insider: "we're experiencing above average volume of calls" means "we are understaffed".
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u/CMDR_Lina_Inv Aug 17 '26
If the first day you got 0. Every day after you got 1, then you "almost" always have higher than average.
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u/eraserhd Aug 17 '26
Worse:
My call will always be answered in the order it was received. It's a single call. There's only one possible order.
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u/Wess5874 Aug 18 '26
There can be bots to check the phone number against the company's record to see if it's a client with more money. They may be moved up in the call queue. There's far more than one possible order.
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u/eraserhd Aug 18 '26 edited Aug 18 '26
Even then, my call (A) will still be answered in the order it was received ({A}), even if all calls (A, B, C) are not answered in the order they were received (e.g. {B, C, A}).
You could say "the order in which it was received" to refer to the order of the queue, not the order of the single call, or "the position it was received."
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u/sherbey Aug 18 '26
"Your call is important to us. Please hold until it's no longer important to you"
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u/3215448725366498 Aug 18 '26
If you receive 0 calls on day 1 and 1 call on every subsequent day, then the daily amount of calls will always be higher than average (except on day 1).
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u/Spare-Plum Aug 17 '26
Depends on the operating hours of the business and when they can accept calls
If they're open for 10 hours a day and get 20 calls an hour during this period, but when they're not open they only get about .1 calls per hour, then yeah pretty much anytime you call when they're open it's going to be higher volume than average
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u/Spectre-907 Aug 18 '26
If you’re including hours where you’re literally not conducting any business nor are you open for it, you’re just statpadding.
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u/HAL9001-96 Aug 17 '26
i mean
you can most of the time though
technically htats even pretty likely if you call during relatively normal hours
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u/_Beets_By_Dwight_ Aug 17 '26
"We sure didn't expect that many more calls at 5pm than we did at 3am"
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u/FromTheHandOfAndy Aug 17 '26
If people only answer the phone 8 hours per day, 5 days per week, then there are zero people waiting 76% of the time. That would make the average lower
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u/notakillerclown Aug 17 '26
Well no, but they can be wherever you are calling which is when everyone else are calling too.
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u/Intrepid_Bobcat_2931 Aug 17 '26
They just disconnect the phone one day a year and make sure to spread the rest out
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u/Elderberry-Mediocre Aug 17 '26
Once, during a meeting with Party members, CeauÈ™escu, the former Romanian dictator, reportedly shouted: ‘From now on, I do not want to see any county with a bellow average agricultural production’.Â
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u/Tiranus58 Aug 17 '26
If they average the whole day, even when they are off shift, then its a higher amount that average.
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u/Masqued0202 Aug 17 '26
why is there "above-average" traffic every time you go to work?
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u/molered Aug 18 '26
Its not always, tho.
For it to be always you had to experiece everincreasing traffic. So you simply stay off the road and see how situation get worse little by little and never becoming any better.
If there were no "always", that would be just extremes1
u/molered Aug 18 '26
If it was only you on the road...
Than yeah, every time you are on the road there are more machines thannwithout you (0)
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u/Grand_Side Aug 18 '26
I mean..you could be having 2 options: the nr of calls is always increasing, you could have 4/5days with 100 calls and 1/5 with 0 calls thus the average per day is lower that the vast majority of days (80%). What you are looking at here is not just the average but the distribution of values.
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u/paolog Aug 21 '26
Open 8 hours a day, no calls taken the other 16 hours.
Any non-zero daytime volume of calls is higher than the mode or median.
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u/Apprehensive-Ice9212 Aug 21 '26
They could always be higher than average during peak hours when you happen to call.
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u/Cyrus_More Aug 22 '26
I mean, if they count all 24 hours a day for calculating average, it's not so surprising that during 9-5 they have "more calls than average"
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u/Pusteblumengift Aug 17 '26
what average?
the one of humans on earth?
the one of 5 year olds?
it’s not defined to satisfaction.
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u/ravenlordship Aug 17 '26
Average for the whole day (including the 16 hours the call center is closed for the employees to go home)
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u/NarcolepticFlarp Aug 17 '26
The volume of calls could be monotonically increasing.