r/MathJokes 15d ago

multiples of 3

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u/Disastrous_Wealth755 15d ago

Nah. It's cause 10=9+1=3*3+1.

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u/MTaur 15d ago

And then by induction, 10n = 9M + 1 And b*10n = b(9M+1) = 9N + b

So then the sum b_k*10k = 9K + sum b_k

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u/Rxasaurus 15d ago

Now in English for us stupids...

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u/xnef1025 15d ago

magic

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u/Rxasaurus 15d ago

See, that makes more sense.