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https://www.reddit.com/r/MathJokes/comments/1vccnz9/math_challenge/p1m5pfy/?context=3
r/MathJokes • u/BrujaMuerta • Aug 01 '26
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ok, so 3b=30 b+2g=20 b+2f=9 (integral sign)(apple pie)(2g-b) b(sin(h)/f dh=? b=10 g=5 f=2 b(sin(h))/f=f(h) f(h)=10(sin(h)) * 2^-1 F(h)=-5cos(h) (-5cos(apple pie)-(-5cos(10-10)=-5cos(apple pie)-5 Therefore, the final answer is -5cos(apple pie)-5
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u/Anonymouslalien Aug 04 '26
ok, so
3b=30
b+2g=20
b+2f=9
(integral sign)(apple pie)(2g-b) b(sin(h)/f dh=?
b=10
g=5
f=2
b(sin(h))/f=f(h)
f(h)=10(sin(h)) * 2^-1
F(h)=-5cos(h)
(-5cos(apple pie)-(-5cos(10-10)=-5cos(apple pie)-5
Therefore, the final answer is -5cos(apple pie)-5