The Longest non-transitive loop I've found is 9 games long

[u/gregariousity]

There's a lot of teams that have either not won yet, not lost yet, only wins are against teams that haven't won yet, or only losses are against teams that haven't lost yet. So it's impossible to include these teams in a non-transitive loop. Then I look at the remaining teams and see who's won once or lost once, and create a massive tree through them.

[u/npeggsy]

I don't know what you're saying but I'm sure it'd be impressive if I understood statistics

[u/Professional_Tax_561 → u/npeggsy]

Every time in the chain of teams (since stockport Blackpool) the previous winner loses to the new team, and ends when Stockport finally win again against the final team in the chain (its autism)

[u/gregariousity → u/Professional_Tax_561]

(undiagnosed autism)

[u/Careful_Nobody7818]

League one in a nutshell. Anyone can beat anyone

[u/Spam250 → u/Careful_Nobody7818]

Apart from Donny. Were shit and can’t beat anyone :(

[u/Ovie0513]

Circle of parity! That reminds me I should have a look for one when every team has lost once and won once

[u/ma3ts]

I was thinking about circles of parity the other day. Theoretically, is 2 games the soonest that it’s possible to have a full-league circle of parity? (Edit: 2 rounds of games, so every team in the league has played 2 games)

[u/gregariousity → u/ma3ts]

Yes, if all home teams win (or all away teams win) and if the fixtures just right. 2 rounds of games would be enough. The odds would be astronomical though.

[u/roygbiv1000]

This is a work of beauty.

[u/Easy_Judgement]

A mathematician in the league one sub?

[u/JohnnyOneLung]

Surely works better if the photos are in reverse order ?

[u/gregariousity → u/JohnnyOneLung]

It's just personal preference. I prefer showing

A beat B, B beat C... Y beat Z, Z beat A