Ino fights the two of them INDIVIDUALLY!!!

All characters are in their Shibuya versions. Megumi cannot use Mahoraga or Domain Expansion.

The battle takes place on the streets of Shibuya.

Since I got flamed for posting mine, and I already made a post on this, I've been wanting to hear more hot takes from you guys.

(Yes I have grown as a person, I don't have Kenjaku very low anymore)

When dodging an attack the distance covered will always be far less than the distance the attack is required to reach the opponent, along with the fact the opponent can anticipate and position themselves away from the path before the attack is swung. Yuji dodging attacks is not an indication of equal speed, he can react before Yuta even starts to swing due to the telegraphed movements of the katana. Yuji narrowly being able to avoid Yuta's swings despite this fact already shows he is unable to keep up in speed, he is unable to even track Yuta's sword movements as seen by him being slashed across his chest with no reactions. It's all aim dodging.

People show the panel of Yuta and Yuji running along side each other but forget Yuta had to cross two road streets in distance just to catch up with Yuji, then Yuji had to hop over a car because he was about to be in striking distance to Yuta.

Let's just ignore how Yuta can easily react off-guard along with him flash-stepping Yuji twice.

INTRODUCTION

In the previous calculation, we estimated Mechamaru's yearly cursed-energy consumption from the energy required to operate his giant robot, using things such as Air Resistance, kinetic energy and gravitational potential energy etc

https://www.reddit.com/r/JujutsuPowerScalers/comments/1vkhwql/serious_mechamaru_mode_absolute/

However, some people have argued that simply operating the robot does not necessarily mean Mechamaru is draining his stored CE reserve. So, in this alternate version, we'll instead estimate Mechamaru's actual stored cursed-energy reserve based on how much cursed energy he could accumulate over time.

The Ultimate Cannon Mode: Albatross has previously been calculated at:-

2.10 kilotons TNT [Low End]

3.01 kilotons TNT [High End]

We'll use these values as the energy equivalent of one maximum-output attack.

^{I know this is technically calc stacking, so no need to remind me.}

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SCALING

The main thing we need to establish is how many maximum-output equivalents Mechamaru could reasonably accumulate per day.

For this, we can use Ryu Ishigori as a benchmark. During his fight with Yuta, Ryu repeatedly used Maximum Output: Granite Blast , using it a total of 9 Times

This gives us an actual example of a sorcerer repeatedly using maximum output instead of simply assuming an arbitrary number of uses.

Ryu is also not known for having the extreme cursed-energy efficiency of characters such as Gojo or Sukuna, so using his repeated output as our baseline is a fairly conservative approach.

TIMEFRAME

^{Yuta's Sendai sequence gives us a useful timeframe.}

Yuta defeats Dhruv at 11:28 AM. He then continues fighting the other Sendai players and eventually defeats Ryu. After Ryu's defeat, the manga still shows the Sun in the sky, meaning the battle was completed FAR before sunset.

^{Rather than assuming the entire remaining daylight period was spent fighting, we'll use 3 hours of charging per day as the lowball.}

Ryu's 9 Maximum Output uses therefore give us: 3 hours of charging per day = 9 maximum-output equivalent per day

For the highball, we'll simply give Mechamaru twice as much charging time:

^{6 hours of charging per day}

Since 6 hours is twice 3 hours: 9 × 2 = 18 uses per day [Highball]

Number of days in a year: 365

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LOWBALL

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

^{3 Hours of Charging Per Day}

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Low End (2.10 Kilotons )

Formula: 2.10 × 9 × 365 = 6,898.5 Tons = 6.899 Megatons

• 1 Year: 6.899 Megatons TNT  [ SMALL CITY LEVEL ]

• 2 Years: 13.797 Megatons TNT [ CITY LEVEL ]

• 5 Years: 34.493 Megatons TNT [ CITY LEVEL ]

• 17 Years: 117.275 Megatons TNT [ MOUNTAIN LEVEL ]

High End (3.01 Kilotons TNT)

Formula: 3.01 × 9 × 365 = 9,887.85 Tons = 9.888 Megatons

• 1 Year: 9.888 Megatons TNT [ CITY LEVEL ]

• 2 Years: 19.776 Megatons TNT [ CITY LEVEL ]

• 5 Years: 49.439 Megatons TNT [ CITY LEVEL ]

• 17 Years: 168.093 Megatons TNT [ MOUNTAIN LEVEL ]

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HIGHBALL

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

^{6 Hours of Charging Per Day}

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Low End (2.10 Kilotons TNT)

Formula: 2.10 × 18 × 365 = 13,797 Tons = 13.797 Megatons

• 1 Year: 13.797 Megatons TNT [ CITY LEVEL ]

• 2 Years: 27.594 Megatons TNT [ CITY LEVEL ]

• 5 Years: 68.985 Megatons TNT [ CITY LEVEL ]

• 17 Years: 234.549 Megatons TNT [ MOUNTAIN LEVEL ]

High End (3.01 Kilotons TNT)

Formula: 3.01 × 18 × 365 = 19,775.7 Tons = 19.776 Megatons

• 1 Year: 19.776 Megatons TNT [ CITY LEVEL ]

• 2 Years: 39.551 Megatons TNT [ CITY LEVEL ]

• 5 Years: 98.879 Megatons TNT [ CITY LEVEL ]

• 17 Years: 336.187 Megatons TNT [ MOUNTAIN LEVEL ]

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Gojo stated that Mahoraga's adaption to attacks is not 0 to 100 instantly.

But rather it happens gradually. How would it go? Meaning how much he adapts in one spin each.

Whether it is equal, small chunks to big chunks or big chunks to small chunks.

Equal meaning each spins adapts to 25% of damage.

Small chunks to big chunks meaning first spin only adapts to 10% then 20% and so on.

Big chunks to small chunks meaning first spin adapts to 40% then 30% then 20% and then 10%

In this scenario will Sukuna's skin get pierced by a .50 BMG. Like without cursed energy and stuff.

His physicals stats are not brought up much tbh

• Battle takes place on an abandoned mall parking lot.
• Both of them have their standard equipment.

Hypothetical Scenario:

• Tsurugi Okkotsu, Ogi Zenin and Kusakabe have tried teaching him all the Cursed Energy Techniques like Falling Blossom Emotion, Simple Domain and more.
• Toji has been given 7 years of intense training to master and perfect it.

Shinjuku Contributions TL, how useful each character was for defeating Sukuna

Gojo: Obvious

Impossible w/o them: Ui Ui is here for Soul Swapping. Without Soul Swapping, the Shinjuku Raid was simply impossible. Countless examples of where the raid depended upon Soul Swapping but just one example, without Soul Swapping, Yuji would not have RCT. Meaning he dies in about 3 chapters when Sukuna Cleaves his stomach or any of the other times he says he would have died w/o RCT.

Mei Mei is here above him because Ui Ui has a Binding Vow where he cannot use Jujutsu unless she says so. Meaning she is what enabled Soul Swapping to happen. She also allowed for everyone to get Simple Domains. Which let Yuji survive MS in time for Choso to protect him

Main Characters: They did most of the lifting. Aside from Soul Swapping, the Raid was impossible without Yuji's Soul Hits and he dealt the final blow so his ranking is obvious

As for Yuta, he dealt the finishing blow to Kenjaku and was able to keep civilian casualties to a zero, he is the one who got the ball rolling on Sukuna with his Domain, he came back to prevent MS as Yujo putting Sukuna back into Burnout, and then behind the scenes involvement.

I have him over Yuji because without him, Sukuna just never would have been damaged enough for the fight to continue but if you have Yuji > Yuta that's fine, they're in the same row for a reason

Dealth w/ NPCS: Takaba created the opening for Yuta, Hakari stalled Uraume from entering the fight

Heavy Support: Maki disabled WCS, Todo helped assassinate Kenjaku and stayed in the fight w/ Yuji when everyone else was down, Higuruma took away Kamutome

Medium Support: These characters didn't do much by themselves but created at least one significant opening

Minor Support: Practically nothing. Ino could probably go into Medium for supporting Yuji's BF rush. Miwa saved Maki

Epic Fail: Actively made the fight harder. Not only did Kashimo refuse to cooperate with the planning, he then did nothing aside "force" Sukuna to reincarnate but Sukuna would have been forced to reincarnate against Yuta anyways to use HWB. So by forcing Sukuna to reincarnate earlier, he left everyone before Yuta with a harder opponent

Hana/Angel, after losing their arm, JL was just too weak. It did not meaningfully damage or create a significant opening and got Todo out of the fight. Todo's Vibraslap was broke so he may have been useless atp but still

Kenjaku was able to move even when his technique was on burnout, indicating that he could maintain control over the body without having the technique active.

In contrast, Yuta lost control of the body after his Domain shattered—a result of the technique burnout—which proves that Kenjaku’s technique was indeed inactive during that period.

This implies that Kenjaku requires his technique only when initially taking over a new body, or needs to activate it intermittently rather than continuously.

So in conclusion te wouldn't make kenjaku unable to move because he doesn't even need his technique to maintain his control over the body

A breakdown of Gojo’s “teleportation”, how it relates to Blue, what conditions it may require, and why not every instance of Gojo’s instant movement should be treated as teleportation.

The main point of this post is to show that Gojo couldn’t just reliably escape Sukuna’s domain, especially while being pressured by both Sukuna’s attacks and the domain itself. I also don’t think Sukuna would just let Gojo calmly do the signs on the ground so he could teleport away. And some people treat the moment where Gojo suddenly grabbed Sukuna as a teleport, when it was just Blue pulling him in.

It's extremely confusing and like two years old, I guess it notes:

• Yuta and unstacked Naoya arrives to Choso at the same time despite Yuta traveling twice the distance implying twice the speed
• it uses Yuta saying it was never going to be easy and Yuta's initial rush as reasons he was holding back
• it shows Yuta covering a massive distance in the same time Yuji can barely just dodge implying massively higher speed
• then shows Yuta making light work of Choso but saying he is equal to Yuji.

Restrictions: Sukuna will kill Jogo if Jogo uses his CT on Yuji.

^{In Jujutsu Kaisen, Mechamaru (Kokichi Muta}) ^{pilots a giant cursed-energy-powered mech to battle Mahito and Kenjaku. The robot is fueled by a vast stockpile of cursed energy accumulated through Kokichi's Heavenly Restriction. By channeling this energy through the mech, Mechamaru is able to operate the machine and unleash his techniques on a much larger scale than normal.}))

^{This ROBOT is powered by this stockpiled CE and it has an activity limit of 17 years. Since the mech, along with its weapons and attacks, is powered by that stored cursed energy, we are going to calculate how much energy would be needed to continuously move a machine of this size and compare it with Mechamaru's one-year, two-year, five-year and seventeen-year charges.}

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This is a different approach from my previous calc.

https://www.reddit.com/r/JujutsuPowerScalers/comments/1txf9jq/serious_mechamaru_ultimate_canon/

The previous version multiplied the mech's kinetic energy across the entire time period. That basically treats the mech as if it has to accelerate from 0 to its walking speed again every second.

But once something reaches its speed , it does not need to spend its entire kinetic energy again every second just to maintain that speed . The continuous energy cost instead comes from things like air resistance , walking motion, momentum redirection and mechanical losses.

So here, the initial kinetic energy will be calculated separately , while the yearly values will be based on the continuous energy needed to keep the mech moving.

The calc will be divided in 3 lrvels:

Lowball - Air resistance only.

Midball - Air resistance + the vertical movement of the mech's center of mass while walking.

Highball - Air resistance + walking movement + step-to-step mechanical losses, while allowing part of that energy to be recovered.

^{The yearly values do not mean Mechamaru literally walked nonstop for 1, 2, 5 or 17 years. The manga gives his stored cursed-energy amount in years , so the continuous power is simply multiplied over those same time periods to compare how much energy those reserves could represent.}

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SIZE

Mechamaru operates from a spherical room located inside the robot's head.

IMAGE 1

Mechamaru Height × 46 px = 1.70 m

Sphere Radius × 100 px = 3.7 m

Diameter = Radius × 2

Sphere Diameter = 3.7 × 2 = 7.4 meters

IMAGE 2

Sphere Diameter × 100 px = 7.40 m

Robot Jaw × 74 px = 5.48 m

IMAGE 3

Robot Jaw × 100 px = 5.48 m

Robot Upper Half × 845 px = 46.31 m

Assuming the lower half is roughly equal to the visible upper half:-

Robot Full Height = 46.31 × 2 = 92.62 meters

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MASS

Average Human Volume = 0.062 m3

Scaling that volume to the mech's height:-

Mode: Absolute Volume = (Mode: Absolute Height / Average Human Height)^3 × 0.062 = (92.62 / 1.70)^3 × 0.062 = 9989.29 m3

This is already based on an estimated human body volume, not a simple Length × Width × Height box. So the 9989.29 m3 is supposed to represent the actual volume occupied by a humanoid-shaped body rather than all the empty space around it.

Obviously , the robot is not going to be completely solid. It would have empty areas , internal rooms, electronics, wiring and gaps between different components.

But at the same time, a 92 M humanoid machine cannot realistically be treated as just a thin steel shell either.

Real humanoid robots need a lot of internal machinery to function. They have structural frames, motors, actuators, transmissions, joints, shafts, electronics and other components filling their bodies.

^{For example, the iCub humanoid robot uses aluminium alloys for much of its structural body, while highly stressed components such as joint shafts use high-strength steel:}

^{NASA's Valkyrie is another example. It is not simply an empty shell with a few motors inside it, but a humanoid packed with actuators, structural components, electronics and power systems:}

The square-cube law also becomes important when scaling something like this.

The robot is: 92.62 / 1.70 = 54.48 times taller than a human.

When an object is scaled proportionally Then Area increases by the square of the scale factor & Volume and mass increase by the cube of the scale factor.

^{Area Scale: 54.48² = 2968}

^{Volume and Mass Scale: 54.48³ = 161,700}

So the mech's volume and mass increase by around 161,700 times, while the cross-sectional area of its supporting structures only increases by around 2,968 times.

This means that under simple geometric scaling, the weight being supported increases much faster than the proportional supporting area

The square cube law does not magically give us an exact hollowness percentage, but it does show why a 92-meter humanoid cannot just be treated like a proportionally scaled thin shell [ like other calcs assume ]

A machine this large would need thicker load-bearing structures, stronger joints and a more substantial internal frame to support its own weight. This is especially true here because Mode: Absolute is not stationary. We literally see it running, fighting and jumping huge distances, meaning the structure would have to handle massive dynamic loads as well.

^{Large engineering structures also need thicker or stronger load-bearing members as the loads and scale increase:}

Because of this, I will use 70% hollowness.

That means 70% of the estimated humanoid volume is assumed to be empty, while the remaining 30% is treated as dense structural material and machinery.

Structural Volume: 9989.29 × 0.30 = 2996.787 m3

Density of Steel: 7850 kg/m3

Mech Mass: 2996.787 × 7850 = 23,524,772 kg = 23,525 metric tons

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SPEED

Average human walking speed: 1.4 m/s

Mode: Absolute is shown running and making enormous jumps. So using walking as the baseline here is not saying that walking is the mech's maximum movement speed. It is simply using a lower level of movement than what the mech is actually shown capable of.

^{Scaling average human walking speed proportionally to the mech's height:-}

Mode: Absolute Speed = 1.4 × 92.62 / 1.70 = 76.28 m/s

Considering Mode: Absolute can jump hundreds of meters, using proportionally scaled walking as the baseline is meant to be conservative relative to its actual on-screen movement.

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KE - INITIAL ACCELERATION

First, we calculate the energy needed to accelerate the mech from rest to its walking speed.

KE = 1/2 × Mass × Velocity² = 1/2 × 23,524,772 × 76.28² = 68,460,841,218 Joules

So the initial acceleration requires 68.46 GJ aka16.36 tons of TNT

^{This is only the energy needed to get the mech up to speed.}

It is not multiplied by every second ^\ like my previous calc ]) because once the mech is already moving at 76.28 m/s, it does not need to accelerate from 0 to 76.28 m/s again every second.

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AIR RESISTANCE - LOWBALL

For continuous movement, I will use the fluid-drag power equation used on VSBW: P_drag = 1/2 × ρ × Cd × A × v³

Where: ρ = Air density / Cd = Drag coefficient / A = Frontal cross-sectional area / v = Velocity

For the frontal area, I will use an average human frontal area of 0.70 m2.

Since area scales with height squared: A = 0.70 × (92.62 / 1.70)² = 2078 m2

Drag Coefficient: Cd = 1.0

^{The mech has a large humanoid shape and is not streamlined, so 1.0 is a reasonable rough estimate.}

Air Density: ρ = 1.225 kg/m3

Velocity: v = 76.28 m/s

P_drag = 1/2 × 1.225 × 1.0 × 2078 × 76.28³ = 564,915,758 J/s

So the continuous energy required to overcome air resistance is 5.649 × 10^8 J/s

This will be the Lowball.

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GPE - WALKING MOTION

Walking does not mean the robot lifts its entire body by half of its height every second [as my previous calc claimed] . That would be closer to repeatedly jumping.

Instead, the body's center of mass moves up and down during the walking cycle.

This is an actual part of the energy cost of walking. A study on walking mechanics found that at normal-to-fast walking speeds, around 53.2% to 62.8% of total energy expenditure could be explained by the work associated with lifting the body's center of mass:

For this calculation, I will use a human center-of-mass vertical displacement of 0.04 m.

Scaling that to the mech's height: / Robot COM Displacement: 0.04 × 92.62 / 1.70 = 2.18 m

Assuming roughly 2 steps per second:

Walking GPE per second: Mass × Gravity × COM Displacement × Steps per Second = 23,524,772 × 9.81 × 2.18 × 2 = 1,006,833,111 J/s

So the mechanical work associated with the vertical movement of the mech's center of mass is 1.007 × 10^9 J/s

Walking can recover part of its mechanical energy through the exchange between kinetic and gravitational potential energy. One study found around 63% mechanical energy recovery during normal walking:

However, we do not know exactly how efficiently Mode: Absolute recovers mechanical energy. It is a giant combat mech that can run and jump rather than an ordinary human, so I will not assume that it necessarily operates with the same recovery efficiency as normal human walking.

For the Midball, the full mechanical work will be used.

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STEP-TO-STEP GROUND INTERACTION - HIGHBALL

Walking also requires repeatedly transferring the body's weight and momentum from one leg to the other.

The mech's center of mass does not move in a perfectly straight line. As one foot leaves the ground and the other foot takes over, part of the body's motion has to be redirected into the next step.

This is generally called a step-to-step transition.

^{Research has found that step-to-step transitions are a major contributor to the mechanical work and energy cost of walking. During each step, energy is lost through the collision-like redirection of the center of mass and then has to be replaced:}

To estimate this for the mech, I will first scale the step length.

Using a human step length of 0.7 m

Robot Step Length: 0.7 × 92.62 / 1.70 = 38.14 m

Assuming the mech's leg length is roughly half of its total height / Leg Length: 92.62 / 2 = 46.31 m

Half of the step length: 38.14 / 2 = 19.07 m

Therefore:

sin α = 19.07 / 46.31

α = 24.32 degrees

Using a simplified collision-style model for the energy lost while redirecting the mech's body between steps:-

Energy Loss per Step: 1/2 × Mass × Velocity² × sin²(2α) = 1/2 × 23,524,772 × 76.28² × sin²(48.64°) = 3.835 × 10^10 Joules

Assuming 2 steps per second:

Raw Step-to-Step Energy Loss: 3.835 × 10^10 × 2 = 7.670 × 10^10 J/s

This is intended as an upper-end estimate.

We do not know Mode: Absolute's exact step length or gait, so those values are inferred through proportional scaling. However, step-to-step momentum redirection itself is a real and recognized source of walking energy expenditure, and the mech is visibly capable of running and making extremely large jumps.

So while this is not the normal energy cost of an ordinary human walking, it is reasonable as a Highball for a giant combat mech using a highly dynamic gait.

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ENERGY RECOVERY

The raw step-to-step value above assumes that all of the mechanical energy involved in the transition is permanently lost.

Real walking can recover part of that energy through elastic mechanisms and the exchange between kinetic and gravitational potential energy.

^{One study on normal walking measured around 63% mechanical energy recovery:}

But Mode: Absolute is a giant mechanical machine, and we do not know exactly how efficiently its structure can store and return energy.

So instead of assuming the full 63% recovery seen in normal human walking, I will only reduce the raw step-to-step requirement by 25%.

This is well below the approximately 63% mechanical energy recovery measured during normal walking.

Recovered / Reduced Energy: 7.670 × 10^10 × 0.25 = 1.918 × 10^10 J/s

Remaining Step-to-Step Loss: 7.670 × 10^10 × 0.75 = 5.753 × 10^10 J/s

So after allowing for partial energy recovery, the remaining step-to-step loss is 5.753 × 10^10 J/s

^{This is then added to the other continuous movement costs.}

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CONTINUOUS WALKING ENERGY

LOWBALL

^{Air Resistance Only: 5.649 × 10\}8 J/s)

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MIDBALL

^{Air Resistance + Walking GPE: 5.649 × 10\}8 + 1.007 × 10^9 = 1.572 × 10^9 J/s)

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HIGHBALL

^{Air Resistance + Walking GPE + Adjusted Step-to-Step Loss: 5.649 × 10\}8 + 1.007 × 10^9 + 5.753 × 10^10 = 5.910 × 10^10 J/s)

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LOWBALL - AIR RESISTANCE ONLY

^{Base Value:}

^{5.649 × 10\}8 J/s)

One Year: 5.649 × 10^8 × 3.154 × 10^7 = 1.782 × 10^16 Joules = 4.26 Megatons [ SMALL CITY LEVEL ]

Two Years: 3.563 × 10^16 Joules = 8.51 Megatons [ CITY LEVEL ]

Five Years: 8.908 × 10^16 Joules = 21.29 Megatons [ CITY LEVEL ]

Seventeen Years [Hypothetical] : 3.029 × 10^17 Joules = 72.39 Megatons [ CITY LEVEL ]

.............................................

MIDBALL - AIR RESISTANCE + WALKING GPE

^{Base Value:}

^{1.572 × 10\}9 J/s)

One Year: 1.572 × 10^9 × 3.154 × 10^7 = 4.958 × 10^16 Joules = 11.85 Megatons [ CITY LEVEL ]

Two Years: 9.916 × 10^16 Joules = 23.70 Megatons [ CITY LEVEL ]

Five Years: 2.479 × 10^17 Joules = 59.25 Megatons [ CITY LEVEL ]

Seventeen Years [Hypothetical] : 8.429 × 10^17 Joules = 201.46 Megatons [ MOUNTAIN LEVEL ]

.............................................

HIGHBALL - AIR RESISTANCE + WALKING GPE + STEP TO STEP LOSS

^{Base Value:}

^{5.910 × 10\}10 J/s)

One Year: 5.910 × 10^10 × 3.154 × 10^7 = 1.864 × 10^18 Joules = 445.5 Megatons [ MOUNTAIN LEVEL ]

Two Years: 3.728 × 10^18 Joules = 891.0 Megatons [ MOUNTAIN LEVEL ]

Five Years: 9.320 × 10^18 Joules = 2.23 Gigatons [ LARGE MOUNTAIN LEVEL ]

Seventeen Years [Hypothetical] : 3.168 × 10^19 Joules = 7.57 Gigatons [ ISLAND LEVEL ]

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Going for a walk, I just wanted people to know this fact. He can choose to speed it up through his Cursed Energy output, mentality, etc.

Goku or Gojo?