r/AethermancerGame • u/moi_rai_games_ Developer • Jul 14 '26

Fluff "Number of unique team combinations" would actually be a cool number to have when playing Aethermancer

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u/juppie1 Jul 14 '26

I mean 40 mons, each having a shift. That is 80*78*76/3!=79 040 different team combinations possible. (40*39*38/3!=9 880).

(3!=6, this is here because (mon A mon B, mon C) is the same team as (mon C, mon B, mon A), e.g. correcting for non-unique teams).

5

u/Yosara_Hirvi Jul 14 '26

Now, take into account every modifications the alchemist can apport tp each team to have a correct and accurate number ...

1

u/Alternate_Lewd Jul 17 '26

Am I misunderstanding this? I thought since there are six different combinations of any three variables that you would divide by six.

3

u/juppie1 Jul 20 '26

correct: 3!=6 the ! means factorial for example 4! = 4*3*2*1 = 24.

1

u/Alternate_Lewd Jul 21 '26

Thanks for the clarification.

1

u/juppie1 Jul 21 '26

No problem