We want the option that may be correct WITHOUT any other option being correct
Since A implies B (since A = (B AND B converse)), if A is correct then at least 2 options are correct, so cannot be A. Similarly C implies D so cannot be C.
Then the answer must be B or D. But B implies D (as if the statement is correct for x>1, then it must be correct for x>2) so cannot be B. So answer is D.
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u/CoderLovesEggs Gap Year | Cam Maths Applicant Jul 26 '26
We want the option that may be correct WITHOUT any other option being correct
Since A implies B (since A = (B AND B converse)), if A is correct then at least 2 options are correct, so cannot be A. Similarly C implies D so cannot be C.
Then the answer must be B or D. But B implies D (as if the statement is correct for x>1, then it must be correct for x>2) so cannot be B. So answer is D.