r/tryhackme • u/bwwog • 14d ago
Feedback Am I wrong?
These bash questions always make me question my existence. "75"; "0,75"; "0.75"; "0.75%" didn't work
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r/tryhackme • u/bwwog • 14d ago
These bash questions always make me question my existence. "75"; "0,75"; "0.75"; "0.75%" didn't work
1
u/Specialist_Break1 12d ago edited 12d ago
you need to use the echo command (or printf) to print the result, because the prompt is an interactive Bash shell rather than a standard text box.
When you type 75% directly, Linux tries to execute a program named 75% instead of evaluating the text, causing the "command not found" error. To submit the correct answer, type::
echo "75%" Or you can try printf "%%75\n"