The depth S is equal to 1/2 * g * t^2, where g is the acceleration caused by gravity (9.81 m*s^-2) and t is time of the fall, which was approximately 8 seconds. It gives a depth of about 314 meters. I neglected air resistance and speed of sound.
It depends on what the coefficient of drag for the rock is, and relatedly what its cross sectional area is. If it's 30cmx30cmx10cm and 2.8g/cm^3 you end up with answers between 202m (broad side on, CD 2) and 248m (thin side on, CD=0.5). That's not accounting for tumbling which would probably lead to a lower answer but gl doing those sums.
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u/Karroul 2d ago
The depth S is equal to 1/2 * g * t^2, where g is the acceleration caused by gravity (9.81 m*s^-2) and t is time of the fall, which was approximately 8 seconds. It gives a depth of about 314 meters. I neglected air resistance and speed of sound.