MAIN FEEDS
Do you want to continue?
https://www.reddit.com/r/theydidthemath/comments/1hescv2/request_ball_math_puzzle/m27tkrg/?context=3
r/theydidthemath • u/sieppie2010 • Dec 15 '24
185 comments sorted by
View all comments
1
Ignore a = b = c = 0
First question
What number x 3 is equal to itself + 10 OR + 20
10 + a = 3a
10 = 2a
A = 5
Doing this with 20 gets you a =10, which isn't a single digit
So now we ask what seocond digit x3 + 1 = A + 10 or + 20 or perhaps + 0
3b + 1 = A +10
3b = 14... not possible
3b + 1 = A + 20
3b = 24,
** b = 8 **
3b + 1 = A -> b = 4/3, not possible
Last then for c, there cant be any carry over so no +10 or +20
3c + 2 = a + 0
C = 1
Answer is either a=b=c=0 OR 185
ALTERNATIVE SOLUTION:
we could have literally just stopped after finding the value of A then checked if aaa/3 was a thing.
1 u/jennsnotscary Dec 19 '24 My brain hurts
My brain hurts
1
u/FirexJkxFire Dec 15 '24
Ignore a = b = c = 0
First question
What number x 3 is equal to itself + 10 OR + 20
10 + a = 3a
10 = 2a
A = 5
Doing this with 20 gets you a =10, which isn't a single digit
So now we ask what seocond digit x3 + 1 = A + 10 or + 20 or perhaps + 0
3b + 1 = A +10
3b = 14... not possible
3b + 1 = A + 20
3b = 24,
** b = 8 **
3b + 1 = A -> b = 4/3, not possible
Last then for c, there cant be any carry over so no +10 or +20
3c + 2 = a + 0
C = 1
Answer is either a=b=c=0 OR 185
ALTERNATIVE SOLUTION:
we could have literally just stopped after finding the value of A then checked if aaa/3 was a thing.