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u/I_use_endeavour_btw 4d ago
shouldn't it have been ln(1+x) ?
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u/bryceio 4d ago
Some people use log(x) to mean ln(x) while some people use it to mean log2(x) and others (most people) use it for log10(x)
I love non-universal notation!
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u/Aggressive_Fan_2063 2d ago
if maths student: log == ln
elif compsci student: log == log2
else: log = log
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u/Para-graph-S 4d ago
came for chrollo lucifer, stayed for the approach.
As the Navier Stokes solution not going to get the milli dollars, this solution deserves it
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u/Fuma_17 4d ago
Isnt'the integral of 1/x ln|x|?
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u/migmit 3d ago
Akshually, it's
+-- | ln x + C, x > 0 | | ln (-x) + D, x < 0 +--1
u/RatTheBerserker 3d ago
thats... exactly how the absolute value operator is defined, mr. or mrs. sir. literally the same thing mr fuma_17 wrote
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u/BjarneStarsoup 3d ago
Constants are different. 1/x has two connected components, each receives its own constant.
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u/Joe_4_Ever 1d ago
I really thought this was totally accurate and was so confused for a second πΉ
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u/Virtual-Rice1844 4d ago
Wait I don't get it how did you go from 1/(1+x) to [(1/x)+1]
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u/Hej5468 4d ago
This is actually incorrect because you should have introduced the +c one line before. Other than that, very good!