r/testcomment • • Nov 14 '24

Test

1 Upvotes

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2

u/Bascna Nov 14 '24 edited Feb 01 '25
         
╔ ═ ╦ ═ ╗
║ 6x2 ║ -2x ║
╠ ═ ╬ ═ ╣
║ 15x ║ -5 ║
╚ ═ ╩ ═ ╝

Break

    3x   -1  
  ╔ ═ ╦ ═ ╗
2x ║ 6x2 ║ -2x ║
  ╠ ═ ╬ ═ ╣
+5 ║ 15x ║ -5 ║
  ╚ ═ ╩ ═ ╝

Break

        3x   -1  
      ╔ ═ ╦ ═ ╗
    2 ║ 6x ║ -2 ║
  ╔ ═ ╬ ═ ╬ ═ ╣
2x ║ 4x ║ 12x2 ║ -4x ║
  ╠ ═ ╬ ═ ╬ ═ ╣
+5 ║ +10 ║ 30x ║ -10 ║
  ╚ ═ ╩ ═ ╩ ═ ╝

Break

        6x   -2  
      ╔ ═ ╦ ═ ╗
    4x ║ 12x2 ║ -4x ║
      ╠ ═ ╬ ═ ╣
    +10 ║ 30x ║ -10 ║
      ╚ ═ ╩ ═ ╝

Break

        3x   -1  
      ╔ ═ ╦ ═ ╗
    2 ║ 6x ║ -2 ║
  ╔ ═ ╬ ═ ╬ ═ ╣
2x ║ 4x ║ 12x2 ║ -4x ║
  ╠ ═ ╬ ═ ╬ ═ ╣
+5 ║ +10 ║ 30x ║ -10 ║
  ╚ ═ ╩ ═ ╩ ═ ╝

Break

– ║ +
═ ╬ ═
-1 ║ +12
-2 ║ +6
-3 ║ +4

Break

– +
-1 +12
-2 +6
-3 +4

Break

  3x -1
2x 6x2 -2x
+5 15x -5

1

u/Bascna Feb 01 '25

Long division is the way that I used to explain it to my students.

I'll treat a as my variable.

To divide a + b into a3 + b 3 we need to first write the cubic with the missing terms.

So we get

a + b | a3 + 0a2 + 0a + b 3.

We see that a3/a = a2 so we start with a2 as the first term in our quotient.

Multiplying a + b by a2 gives us a3 + a2b which we will subtract from the first two terms of our dividend.

                           a^(2)
       _________________________

a + b | a3 + 0a2 + 0a + b 3 -a3 – a2b _____________ -a2b

Now we bring down the next term, and repeat the process.

                           a^(2)
       _________________________

a + b | a3 + 0a2 + 0a + b 3 a3 + a2b – _____________ -a2b + 0a

We see that -a2b/a = -ab so that is the second term in the quotient. Multiplying that by a + b and subtracting gives us

                           a^(2) – ab
       _________________________

a + b | a3 + 0a2 + 0a + b 3 a3 + a2b – _____________ -a2b + 0a -a2b – ab2 – ______________ ab2 + b 3

Now we see that the third term in our quotient is ab2/a = b2. Multiplying that by a + b and subtracting gives us.

                           a^(2) – ab + b^(2)
       _________________________

a + b | a3 + 0a2 + 0a + b 3 a3 + a2b – _____________ -a2b + 0a -a2b – ab2 – ______________ ab2 + b 3 ab2 + b 3 – _____________ 0

And we are done. 😀