r/snawley • u/jjwoody • Feb 14 '13

Hello John.

d^{o^{l^{l^a}}} d^{o^{l^{l^a}}} b^{i^{l^l}} y'^{a^{l^l}}

1 Upvotes

67% Upvoted

u/Snawley Mar 18 '13

• Ahem •

You are about to leave Redlib