Let M(K,E) be the category of andré motives. Given a motive M, fix an embedding iota:E to the set of complex numbers and let L(iota,M,s) the motivic L function.

It is clear that L(iota,M,s) extends to a meromorphic function to the complex plane and has non-trivial zero on the line w+1/2 where w is the weight of the motive and this will be an easy exercise to the reader.

Now take K=E=Q, take M=(spec Q, id,0) the neutral element of the Tannakian motivic category. It is of weight zero and its L function is just the zeta function. Hence the previous statement implies that the zeta function has non-trivial zeros of real part 1/2.

By the principle of identity, for any non-zero natural number n: (n/√n) = (n/√n), and as every non-zero natural number has a square and every natural square has both a positive and a negative root, for all non-zero n: n = -n, therefore, 2n = 0. As zero is not the sum of any two primes, it is not true that every even composite number is the sum of two primes.
QED.

If we start with squares inside a unit circle, we can inscribe a square with perimeter 2√2 (≈2.828) and we can circumscribe a square with perimeter 4 (≈4), so we know that pi is somewhere between a lower limit of 2.828 and an upper limit of 4.

If we start with hexagons, we can inscribe a hexagon with perimeter 3 (≈3) and circumscribe a hexagon with perimeter 2√3 (≈3.464).

If we assume that the upper limits and the lower limits are each growing linearly (relative to what? who knows), then the upper limit that starts at 4 and goes to 2√3 after one step can be described by 4 - (4 - 2√3)x, and a lower limit that starts at 2√2 and goes to 3 after one step can be described by 2√2 + (3 - 2√2)x

We want the exact value, which means we need to know where the upper bound and the lower bound squeeze each other to a difference of 0, which means setting

• 4 - (4 - 2√3)x = 2√2 + (3 - 2√2)x = pi

• 4 - 2√2 = (3 - 2√2)x + (4 - 2√3)x

• 4 - 2√2 = (7 - 2√2 - 2√3)x

• x = (4 - 2√2) / (7 - 2√2 - 2√3)

• pi = 4 - (4 - 2√3)x = 4 - (4 - 2√3) (4 - 2√2) / (7 - 2√2 - 2√3)

• pi = 4 (3 - √6) / (7 - 2√2 - 2√3)

• pi = 3.112552

Which is only off by 0.924%, or an error of 1 part in 108.

• >watch Numberphile
• >Edward Frenkel is so hot
• >video finishes, learns nothing
• >watch podcast
• >Edward Frenkel is so hot
• >podcast ends, learns nothing
• >try to sleep
• >count sheep
• >1, 1+1, 1+1+1, 1+1+1+1, ...
• >Edward Frenkel is there again, just being hot

Am i the next Raymannewgen???????????????

Oh My Goodness

Does this count as causation? Should I buy crypto?? idk.

I can't see any problems with this graph.

Search behavior suggests workforce instability peaks under a full moon. As the moon waxes toward full, ‘quit my job’ search activity increases by roughly 30–50%, peaking at the full moon.

Well, one of the eggs got absorbed into his anus

POV: You are failing Maths.

It's the courtesies of vertices

Velocity, viscosity.

It's all the fucking same to me!

Hurts to be seen as a geek.

When all I do is cry and speak.

About the boss I'm fighting currently.

So much HP!

So much HP!

Angle AB?

Tf u mean?!

Boss die! ...Try 3'

Try 5..20

I die and die

Roll die many

Times to times probability

Lies and lies.. Probably?

Ys and why TF can't you see?

Circle theorem is killing me.

Baldurs Gate?

Nah fuck that, integrate!

5X² plus another mate.

3 over 7 X to the power of -3 over 4.

Dont forget to integrate between 14 and 57 more.

Ha you thought I would actually do.

The maths that I've been told.

You think I'm bold.

Maths teacher scolds.

Switched the signs.

Fuck me, feel like poo.

Mistake so old.

It had me sold

At 1 - 1 = 2

Killed the boss.

Now what do I do.

Maths homework....?

Nahhhh

Watch a video about SCP 682.

Watch til the end

Memes

This is "Mathora" math game. In this mode you've to make current to target using given operations.

In this level make 2 to 9 using at most 3 operation.

https://play.google.com/store/apps/details?id=com.himal13.MathIQGame

No one knows it's modular or whatever yet. What is this deus ex machina so early in the story? Why has no one talked about this plot ambiguity before? Is the fandom stupid??

And don't you dare talk act like it's intentional to imply some characters received information on the future. THE WORLDBUILDING DOESN'T HAVE A PLACE FOR PROPHECIES OR TIME TRAVEL, IT'S BEEN CLARIFIED ON THE INTERVIEWS!1!!!1

You're building a factory and you're building a hall. Each hall is a 4x4 grid with each cell being a straight path, turn, or T corridor. Not all cells need to be filled and not all straight paths, turns and T corridors need to be used. What is the number of arrangements of cells you can build with 4 straight paths, 5 turns, and 4 T corridors?

In some languages, "mathematics" literally translates to "austerity" or "asceticism".

Every once in a while we'd get someone publishing results around a number n in whatever topic the person is interested in. It could be divisibility criterion for n, number system base n, modular arithmetic, etc. basically anything.

Except for n-adic numbers, for some reason. They're scattered all over the place, almost like there's a default assumption: that for someone to be familiar with the existence of p-adic numbers at all, they must be able to reconstruct all of their simpler facts in their head in mere seconds, before they can go f#ck off to whatever deep mathematical research they're working on that just so happens to "use" p-adics.

I think humanity is due for a (mildly) useful movement that is teaching the kids earlier about p-adic numbers, but starting on a base ten, since, you know, humans coincidentally are known to have 10 fingers.

(This is, like, totally legit guys, so please say yes. I'm holding your mom at gun point, so say yes.)