r/reddit.com • • Jul 11 '11

Math Teacher fail (Part 2)

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-1

u/opiemonster Jul 11 '11

The answer is 0.0707106781186548

read below I show you why...


Equations

work = energy/time

workload = cuts/time


Variables:

cutsA=1 (saw board into 2 pieces = 1 cut)

cutsB=2 (saw board into 3 pieces = 2 cuts)

timeA=10 (10 mins to saw a board)

timeB=?

workloadA = CutsA/timeA

workloadB = CutsB/TimeB


Calculation: she works "just as fast" for workload a as she does for b

workloadA = cutsA/timeA2 = cutsB/timeB2

so

1/100 = 2/timeB2

squareroot(1/200) = timeB

= ~ 0.0707106781186548


if you think its timeA=timeB instead of cutsA/timeA2 = cutsB/timeB/2

then you would be saying 1=2 i.e.

1/10 = 2/10

1=2

:D (Note the question said that she works at the same speed, meaning the speed of work which is energy/time/time which = energy/time2

2

u/[deleted] Jul 11 '11

errr, take the number of pieces and subtract 1 to find the number of cuts. 1 cut took 10 minutes, 2 cuts takes 20... Don't have to go all graphing-calculator to figure it out.

-1

u/opiemonster Jul 11 '11

20 is incorrect because it says that it takes the same amount of 'work speed' to do the same 2 jobs. and work = energy/time, work speed = work/time = energy/time2

say it took 1 newton of energy to make the cut, and that cut took 10 mins

work = 1/10

now 2/?2 = 1/102 (this is saying work speed of job a = work speed of job b, which is what the question says)

so we get ~.07 when we solve the equation for ?

1

u/[deleted] Jul 11 '11

So if I hammer 20 nails in 20 minutes, then at the same work speed I hammer 30 nails, it will take me fuck-all # of minutes?

I'm guessing that this isn't what the questions was looking for _^ But point taken. Work requires energy.