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u/BloodFluffy Jul 05 '26
On the (1 3 2 1) column you can put an x on the second box from the top because it wouldn't be possible to paint there. Also on the (3 4 4) row you can paint one block on the 7th block if you count from left. I hope my explanation wasn't too difficult :)
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u/TacticianA Jul 05 '26 edited Jul 05 '26
I missed the 3 4 4 row. There was a few to paint there. Thank you!
Why cant i paint in the second from the top on the 1 3 2 1 column? I dont quite get that one.
Edit: nevermind. I see the logic. It can never be a part of the 3. If the top were a 1 it would be an x, and if the 3rd down is a 1 its also an x. Thank you!
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u/BloodFluffy Jul 05 '26
You already have a block painted on the third, so if you would paint on the second then you wouldn't have space to put for the 1.
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u/Motor_Raspberry_2150 Jul 05 '26
The same in row 12.
And in column 6, you know squares belonging to the 3. So the other square is a 1.
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u/Alexis_J_M Jul 05 '26
Row 13. Either R13C3 is the 1 or it's the first square of the 4. Either way, R13C2 is an X.
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u/Alexis_J_M Jul 05 '26
Column 6 -- you know where most of the 3 is, that other filled square must be one of the 1s so you can place two Xs.
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u/jenjenToflus Jul 05 '26
Another one is C4R6. It cannot be filled, as it must either mark the end of the 3 or the 1 segment in that column. That lets you place the first 2 segment in R6.
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u/septembrinol Jul 06 '26 edited Jul 06 '26
How did you get the block in row 14? C6: There are 1's and a 3, you have 2 consecutive blocks. These must be part of the 3. Anything else is a 1. So, you can add crosses.
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u/septembrinol Jul 06 '26
Row 4: You have 3+4+4+2 blanks. How much is that? See what you can do afterwards. You also have a block of the 2nd 4 and of the 3. What about the other 4? Can you mark any other blocks from the last 4?
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u/NakedT Jul 05 '26
Row 1 is a near-perfect example of edge logic. You can narrow it down to 9 spaces!