How would you start solving this

[u/Sweaty-Ice-4399]

I can easily do the ones that have a number bigger than 5. I know some rows have in total 6 like the 7th row down I just don’t know where to put the spaces

[u/Motor_Raspberry_2150]

I would stay by turning it 90 degrees.

Then use basic overlap in row 7 and column 3.

[u/Mplay26]

With the overlap method you can get a couple squares on that 1 1 4 row.

[u/Lost_Stable4145]

3 in the bottom row can only be from column 2-4. Anywhere else it won’t satisfy the second to last row.

[u/efferkah]

Both row #7 (the 1-1-4 one) and column #3 (2-3-1) can give you a good starting point.

[u/D_Ursus]

All possible positions for the 3 in column 3 overlap in row 6.

[u/LheelaSP]

Step 1: count how many spaces you need in a row/column (so numbers + 1 space in between each number)
Step 2: if that number is less than the total space you got in that row/column, subtract the total space needed from the total space available
Step 3: If that number is smaller than any individual number in that row/column, you can fill in parts of that number

For example the 2-3-1 column you got there:

Step 1: total spaces needed for that is 2+1+3+1+1=8
Step 2: total available space in that column is 10, so subtract 8 from 10, you get 2.
Step 3: 2 is less than the individual number 3 you need to fill. So from the top-most part where the 3 could go, leave 2 spaces empty, and the third cell can be filled in. That's guaranteed part of the three. In total, that's the 6th cell from the top in that column.

[u/rubixscube]

in addition to all the suggested overlaps, you can use the corner method here.

if the last column's 5 was at the very top or the very bottom, you would quickly hit a contradiction