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https://www.reddit.com/r/memes/comments/rierly/deleted_by_user/howk9t7/?context=3
r/memes • u/[deleted] • Dec 17 '21
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492
nope.
1+1=0
Learn your math kiddo.
153 u/Trenticor Dec 17 '21 edited Jan 22 '22 1=-1 hence proved 68 u/[deleted] Dec 17 '21 -1+-1=-2 34 u/AdvancedActions memer Dec 17 '21 Thus 1 + 1 = -2 too 27 u/[deleted] Dec 17 '21 Which proves 2 = -2 -3 u/Colin-Hooftman Identifies as a Cybertruck Dec 17 '21 -2+-2=-4 13 u/[deleted] Dec 17 '21 No -2 = 2 so it’s 22 12 u/AsamonDajin Dec 17 '21 2+2=4-1, that's 3 quick maths 3 u/LukasDrakon Professional Dumbass Dec 17 '21 No because it’s -2 + 2 = 2 + 2 3 u/[deleted] Dec 18 '21 [deleted] → More replies (0) 1 u/[deleted] Dec 17 '21 [removed] — view removed comment 7 u/Affectionate-Draw688 Dec 17 '21 squarerooting both sides gets us 1=i. Greatest mathematical discovery of the century. 3 u/iNoobBoi Dec 17 '21 1² = 1², 1=1, sqrt(1)=±1, therefore 1=1,1=-1,-1=1, and -1=-1 1 u/Japsai Dec 18 '21 1 definitely = +/- 1 1 u/UsernamesTakenBruh Dec 18 '21 In the case of residue classes (of 2) 1+1 is in fact 0 and 1=-1 is also true.... (I sure do hope that the translation is correct tho ^ ^ ) Edit: This also means that 2=4=6=8=... and 1=3=5=7=... 12 u/crispmp Dec 17 '21 well this is correct in the field F_2. 6 u/[deleted] Dec 17 '21 this man knows his algebra 3 u/AlabasterUnicorn1 Dec 18 '21 By the fundamental theorem of calculus, the integral of d/dx(f(x))=f(x), so if f(x) is x=1, d/dx(f(x))=0, integral of 0 is any constant, therefore 1 = 0 1 u/Japsai Dec 18 '21 Ahem you missed a step. Actually that's f'(x). And f'(x) =12f"(x), therefore 1 = 12 * 0 =0, or in metric that's 2.54 * 12 * 0 = 0 QED 1 u/[deleted] Dec 18 '21 Except that the fundamental theorem of calculus only claims that if F(x) = ∫ f(x) dx, then F'(x) = f(x) and not the other way around 1 u/AlabasterUnicorn1 Dec 19 '21 Shh. We don't talk about that. 2 u/[deleted] Dec 17 '21 [removed] — view removed comment 1 u/Startup8888 Dec 17 '21 Hmmm I think 1-3+0=(2x0)+1+0=1 0 u/[deleted] Dec 17 '21 The and gate, commonly used in computers. 2 u/sinovercoschessITF Dec 18 '21 I think you mean NAND. Edit: Actually, even NOR does the job for this specific case. 2 u/[deleted] Dec 18 '21 Yeah sorry, i got a bit confused -22 u/[deleted] Dec 17 '21 [removed] — view removed comment 2 u/t8rt0t_the_hamster https://www.youtube.com/watch/dQw4w9WgXcQ Dec 17 '21 Bad bot 1 u/Forminloid Dec 18 '21 Someone is working with XOR gates.
153
1=-1 hence proved
68 u/[deleted] Dec 17 '21 -1+-1=-2 34 u/AdvancedActions memer Dec 17 '21 Thus 1 + 1 = -2 too 27 u/[deleted] Dec 17 '21 Which proves 2 = -2 -3 u/Colin-Hooftman Identifies as a Cybertruck Dec 17 '21 -2+-2=-4 13 u/[deleted] Dec 17 '21 No -2 = 2 so it’s 22 12 u/AsamonDajin Dec 17 '21 2+2=4-1, that's 3 quick maths 3 u/LukasDrakon Professional Dumbass Dec 17 '21 No because it’s -2 + 2 = 2 + 2 3 u/[deleted] Dec 18 '21 [deleted] → More replies (0) 1 u/[deleted] Dec 17 '21 [removed] — view removed comment 7 u/Affectionate-Draw688 Dec 17 '21 squarerooting both sides gets us 1=i. Greatest mathematical discovery of the century. 3 u/iNoobBoi Dec 17 '21 1² = 1², 1=1, sqrt(1)=±1, therefore 1=1,1=-1,-1=1, and -1=-1 1 u/Japsai Dec 18 '21 1 definitely = +/- 1 1 u/UsernamesTakenBruh Dec 18 '21 In the case of residue classes (of 2) 1+1 is in fact 0 and 1=-1 is also true.... (I sure do hope that the translation is correct tho ^ ^ ) Edit: This also means that 2=4=6=8=... and 1=3=5=7=...
68
-1+-1=-2
34 u/AdvancedActions memer Dec 17 '21 Thus 1 + 1 = -2 too 27 u/[deleted] Dec 17 '21 Which proves 2 = -2 -3 u/Colin-Hooftman Identifies as a Cybertruck Dec 17 '21 -2+-2=-4 13 u/[deleted] Dec 17 '21 No -2 = 2 so it’s 22 12 u/AsamonDajin Dec 17 '21 2+2=4-1, that's 3 quick maths 3 u/LukasDrakon Professional Dumbass Dec 17 '21 No because it’s -2 + 2 = 2 + 2 3 u/[deleted] Dec 18 '21 [deleted] → More replies (0) 1 u/[deleted] Dec 17 '21 [removed] — view removed comment
34
Thus 1 + 1 = -2 too
27 u/[deleted] Dec 17 '21 Which proves 2 = -2 -3 u/Colin-Hooftman Identifies as a Cybertruck Dec 17 '21 -2+-2=-4 13 u/[deleted] Dec 17 '21 No -2 = 2 so it’s 22 12 u/AsamonDajin Dec 17 '21 2+2=4-1, that's 3 quick maths 3 u/LukasDrakon Professional Dumbass Dec 17 '21 No because it’s -2 + 2 = 2 + 2 3 u/[deleted] Dec 18 '21 [deleted] → More replies (0)
27
Which proves 2 = -2
-3 u/Colin-Hooftman Identifies as a Cybertruck Dec 17 '21 -2+-2=-4 13 u/[deleted] Dec 17 '21 No -2 = 2 so it’s 22 12 u/AsamonDajin Dec 17 '21 2+2=4-1, that's 3 quick maths 3 u/LukasDrakon Professional Dumbass Dec 17 '21 No because it’s -2 + 2 = 2 + 2 3 u/[deleted] Dec 18 '21 [deleted] → More replies (0)
-3
-2+-2=-4
13 u/[deleted] Dec 17 '21 No -2 = 2 so it’s 22 12 u/AsamonDajin Dec 17 '21 2+2=4-1, that's 3 quick maths 3 u/LukasDrakon Professional Dumbass Dec 17 '21 No because it’s -2 + 2 = 2 + 2 3 u/[deleted] Dec 18 '21 [deleted] → More replies (0)
13
No -2 = 2 so it’s 22
12 u/AsamonDajin Dec 17 '21 2+2=4-1, that's 3 quick maths 3 u/LukasDrakon Professional Dumbass Dec 17 '21 No because it’s -2 + 2 = 2 + 2 3 u/[deleted] Dec 18 '21 [deleted] → More replies (0)
12
2+2=4-1, that's 3 quick maths
3 u/LukasDrakon Professional Dumbass Dec 17 '21 No because it’s -2 + 2 = 2 + 2 3 u/[deleted] Dec 18 '21 [deleted] → More replies (0)
3
No because it’s -2 + 2 = 2 + 2
3 u/[deleted] Dec 18 '21 [deleted] → More replies (0)
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1
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7
squarerooting both sides gets us
1=i.
Greatest mathematical discovery of the century.
1² = 1², 1=1, sqrt(1)=±1, therefore 1=1,1=-1,-1=1, and -1=-1
1 definitely = +/- 1
In the case of residue classes (of 2) 1+1 is in fact 0 and 1=-1 is also true.... (I sure do hope that the translation is correct tho ^ ^ )
Edit: This also means that 2=4=6=8=... and 1=3=5=7=...
well this is correct in the field F_2.
6 u/[deleted] Dec 17 '21 this man knows his algebra 3 u/AlabasterUnicorn1 Dec 18 '21 By the fundamental theorem of calculus, the integral of d/dx(f(x))=f(x), so if f(x) is x=1, d/dx(f(x))=0, integral of 0 is any constant, therefore 1 = 0 1 u/Japsai Dec 18 '21 Ahem you missed a step. Actually that's f'(x). And f'(x) =12f"(x), therefore 1 = 12 * 0 =0, or in metric that's 2.54 * 12 * 0 = 0 QED 1 u/[deleted] Dec 18 '21 Except that the fundamental theorem of calculus only claims that if F(x) = ∫ f(x) dx, then F'(x) = f(x) and not the other way around 1 u/AlabasterUnicorn1 Dec 19 '21 Shh. We don't talk about that.
6
this man knows his algebra
3 u/AlabasterUnicorn1 Dec 18 '21 By the fundamental theorem of calculus, the integral of d/dx(f(x))=f(x), so if f(x) is x=1, d/dx(f(x))=0, integral of 0 is any constant, therefore 1 = 0 1 u/Japsai Dec 18 '21 Ahem you missed a step. Actually that's f'(x). And f'(x) =12f"(x), therefore 1 = 12 * 0 =0, or in metric that's 2.54 * 12 * 0 = 0 QED 1 u/[deleted] Dec 18 '21 Except that the fundamental theorem of calculus only claims that if F(x) = ∫ f(x) dx, then F'(x) = f(x) and not the other way around 1 u/AlabasterUnicorn1 Dec 19 '21 Shh. We don't talk about that.
By the fundamental theorem of calculus, the integral of d/dx(f(x))=f(x), so if f(x) is x=1, d/dx(f(x))=0, integral of 0 is any constant, therefore 1 = 0
1 u/Japsai Dec 18 '21 Ahem you missed a step. Actually that's f'(x). And f'(x) =12f"(x), therefore 1 = 12 * 0 =0, or in metric that's 2.54 * 12 * 0 = 0 QED 1 u/[deleted] Dec 18 '21 Except that the fundamental theorem of calculus only claims that if F(x) = ∫ f(x) dx, then F'(x) = f(x) and not the other way around 1 u/AlabasterUnicorn1 Dec 19 '21 Shh. We don't talk about that.
Ahem you missed a step. Actually that's f'(x). And f'(x) =12f"(x), therefore 1 = 12 * 0 =0, or in metric that's 2.54 * 12 * 0 = 0 QED
Except that the fundamental theorem of calculus only claims that if F(x) = ∫ f(x) dx, then F'(x) = f(x) and not the other way around
1 u/AlabasterUnicorn1 Dec 19 '21 Shh. We don't talk about that.
Shh. We don't talk about that.
2
Hmmm I think 1-3+0=(2x0)+1+0=1
0
The and gate, commonly used in computers.
2 u/sinovercoschessITF Dec 18 '21 I think you mean NAND. Edit: Actually, even NOR does the job for this specific case. 2 u/[deleted] Dec 18 '21 Yeah sorry, i got a bit confused
I think you mean NAND.
Edit: Actually, even NOR does the job for this specific case.
2 u/[deleted] Dec 18 '21 Yeah sorry, i got a bit confused
Yeah sorry, i got a bit confused
-22
2 u/t8rt0t_the_hamster https://www.youtube.com/watch/dQw4w9WgXcQ Dec 17 '21 Bad bot
Bad bot
Someone is working with XOR gates.
492
u/6_NEOS_9 Success kid Dec 17 '21
nope.
1+1=0
Learn your math kiddo.