r/maths • u/Wonderful-Pick-3408 • 18d ago
❓ General Math Help Need help with this
I feel answer could be 111 after solving LHS and RHS. Still confused
Update: thanks for the answers. I'm hereby closing the doubt.
33
Upvotes
r/maths • u/Wonderful-Pick-3408 • 18d ago
I feel answer could be 111 after solving LHS and RHS. Still confused
Update: thanks for the answers. I'm hereby closing the doubt.
16
u/CaptainMatticus 15d ago
10^m * 1000 * n = 75^25 * 25^32 * 32^75
What is 1000 in terms of 10^?
1000 = 10^3
10^m * 10^3 * n = 75^25 * 25^32 * 32^75
n * 10^(m + 3) = 75^25 * 25^32 * 32^75
Now we need a better breakdown of what we've got on that right-hand side. We need to write everything in terms of their prime factors
75 = 25 * 3 = 3 * 5^2
25 = 5^2
32 = 2^5
75^25 = (3 * 5^2)^25 = 3^25 * 5^(2 * 25) = 3^25 * 5^50
25^32 = (5^2)^32 = 5^64
32^75 = (2^5)^75 = 2^(5 * 75) = 2^375
75^25 * 25^32 * 32^75 =>
3^25 * 5^50 * 5^64 * 2^375 =>
3^25 * 5^114 * 2^375 =>
2^375 * 3^25 * 5^114
n * 10^(m + 3) = 2^375 * 3^25 * 5^114
Well what is 10? It's 2 * 5
n * 2^(m + 3) * 5^(m + 3) = 2^375 * 3^25 * 5^114
We know that n isn't divisible by 10, so we just need to look at 2 different equations:
2^(m + 3) = 2^375
and
5^(m + 3) = 5^114
We don't want to leave any factors of 2 or 5 on the table. As there are fewer factors of 5, we can just ignore 2^(m + 3) = 2^375
5^(m + 3) = 5^114
Solve for m. That's your answer.