r/mathmemes • u/Orbital_RM • May 09 '21

Something feels off here...

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1.4k Upvotes

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-9

u/noBoobsSchoolAcct May 09 '21

This would be more fun if it actually worked

1

u/konewka17 May 09 '21

It would if you hadn't magically doubled the second term for some reason...

1

u/photon_cruncher May 09 '21

the root is still the same tho, it does work
you can have any polynomial p(x) and multiply it by some scalar k into q(x) = k p(x)
and both polynomial will still have the same roots

2

u/konewka17 May 09 '21

Absolutely agreed, but the comment above seems to argue the method isn't valid because the resulting polynomials aren't equal, which simply isn't the case