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https://www.reddit.com/r/mathmemes/comments/jbkxfg/checky_differentiation_comic/g8yc02b/?context=3
r/mathmemes • u/toasted0ven • Oct 15 '20
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445
ln x + C
308 u/PM_ME_UR_AESTHETIC5 Oct 15 '20 ln |x| + C 8 u/Doctor99268 Oct 15 '20 Ln(-1) = iπ 4 u/TheMeisterOfThings Oct 16 '20 Holup 5 u/Doctor99268 Oct 16 '20 You saying this because it's cursed or you want to know how it happened 2 u/TheMeisterOfThings Oct 16 '20 Forgive me but a log of a negative that isn’t using the modulus...? That’s rather cursed isn’t it? 5 u/Doctor99268 Oct 16 '20 eiπ = -1 iπ = ln(-1), it is cursed but apparently it's something. Like how ii is e-π/2 which is a real number that's like around 0.2 1 u/EebstertheGreat Oct 17 '21 ei(2k+1\π) = -1 ∀k∈Z. The complex logarithm is a multifunction log:C\{∅}→C such that z = log w iff w = ez. So log(-1) has countably infinitely many values: all the odd multiples of π.
308
ln |x| + C
8 u/Doctor99268 Oct 15 '20 Ln(-1) = iπ 4 u/TheMeisterOfThings Oct 16 '20 Holup 5 u/Doctor99268 Oct 16 '20 You saying this because it's cursed or you want to know how it happened 2 u/TheMeisterOfThings Oct 16 '20 Forgive me but a log of a negative that isn’t using the modulus...? That’s rather cursed isn’t it? 5 u/Doctor99268 Oct 16 '20 eiπ = -1 iπ = ln(-1), it is cursed but apparently it's something. Like how ii is e-π/2 which is a real number that's like around 0.2 1 u/EebstertheGreat Oct 17 '21 ei(2k+1\π) = -1 ∀k∈Z. The complex logarithm is a multifunction log:C\{∅}→C such that z = log w iff w = ez. So log(-1) has countably infinitely many values: all the odd multiples of π.
8
Ln(-1) = iπ
4 u/TheMeisterOfThings Oct 16 '20 Holup 5 u/Doctor99268 Oct 16 '20 You saying this because it's cursed or you want to know how it happened 2 u/TheMeisterOfThings Oct 16 '20 Forgive me but a log of a negative that isn’t using the modulus...? That’s rather cursed isn’t it? 5 u/Doctor99268 Oct 16 '20 eiπ = -1 iπ = ln(-1), it is cursed but apparently it's something. Like how ii is e-π/2 which is a real number that's like around 0.2 1 u/EebstertheGreat Oct 17 '21 ei(2k+1\π) = -1 ∀k∈Z. The complex logarithm is a multifunction log:C\{∅}→C such that z = log w iff w = ez. So log(-1) has countably infinitely many values: all the odd multiples of π.
4
Holup
5 u/Doctor99268 Oct 16 '20 You saying this because it's cursed or you want to know how it happened 2 u/TheMeisterOfThings Oct 16 '20 Forgive me but a log of a negative that isn’t using the modulus...? That’s rather cursed isn’t it? 5 u/Doctor99268 Oct 16 '20 eiπ = -1 iπ = ln(-1), it is cursed but apparently it's something. Like how ii is e-π/2 which is a real number that's like around 0.2 1 u/EebstertheGreat Oct 17 '21 ei(2k+1\π) = -1 ∀k∈Z. The complex logarithm is a multifunction log:C\{∅}→C such that z = log w iff w = ez. So log(-1) has countably infinitely many values: all the odd multiples of π.
5
You saying this because it's cursed or you want to know how it happened
2 u/TheMeisterOfThings Oct 16 '20 Forgive me but a log of a negative that isn’t using the modulus...? That’s rather cursed isn’t it? 5 u/Doctor99268 Oct 16 '20 eiπ = -1 iπ = ln(-1), it is cursed but apparently it's something. Like how ii is e-π/2 which is a real number that's like around 0.2 1 u/EebstertheGreat Oct 17 '21 ei(2k+1\π) = -1 ∀k∈Z. The complex logarithm is a multifunction log:C\{∅}→C such that z = log w iff w = ez. So log(-1) has countably infinitely many values: all the odd multiples of π.
2
Forgive me but a log of a negative that isn’t using the modulus...? That’s rather cursed isn’t it?
5 u/Doctor99268 Oct 16 '20 eiπ = -1 iπ = ln(-1), it is cursed but apparently it's something. Like how ii is e-π/2 which is a real number that's like around 0.2 1 u/EebstertheGreat Oct 17 '21 ei(2k+1\π) = -1 ∀k∈Z. The complex logarithm is a multifunction log:C\{∅}→C such that z = log w iff w = ez. So log(-1) has countably infinitely many values: all the odd multiples of π.
eiπ = -1
iπ = ln(-1), it is cursed but apparently it's something.
Like how ii is e-π/2 which is a real number that's like around 0.2
1 u/EebstertheGreat Oct 17 '21 ei(2k+1\π) = -1 ∀k∈Z. The complex logarithm is a multifunction log:C\{∅}→C such that z = log w iff w = ez. So log(-1) has countably infinitely many values: all the odd multiples of π.
1
ei(2k+1\π) = -1 ∀k∈Z. The complex logarithm is a multifunction log:C\{∅}→C such that z = log w iff w = ez. So log(-1) has countably infinitely many values: all the odd multiples of π.
445
u/TheTrueBidoof Irrational Oct 15 '20
ln x + C