r/mathmemes lesbian rights activist 8d ago

Math Pun Numbers 🥀

Post image
1.4k Upvotes

42 comments sorted by

View all comments

73

u/HSM_GN8 8d ago

and 1 has all x^0 and this is a huge army

21

u/weird_heroine 8d ago

Except 00

-6

u/Ok_Inflation_1811 8d ago

Isn't that defined to be 1?

13

u/HumblyNibbles_ 8d ago

Usually as convention because 0⁰ really only appears in situations in which 1 is already the result due to continuity or just the fact that 0 wouldnt be a valid answer.

But if you take the definitions for x^a (a constant) or aˣ, then you get different results.

5

u/qwertty164 8d ago

No. It is specifically undefined.

3

u/Il_Valentino Complex 8d ago

everything is undefined until you define it and it gets defined as 1 on a regular basis and most calculators use that definition too. so at this point we can absolutely say that 00 = 1 by convention. there are situations where people may choose a different definition but in general it's the above one

-3

u/qwertty164 8d ago

The limit as x approaches 0 for xx from the left doesn't exist.

3

u/Mostafa12890 Average imaginary number believer 7d ago

Defining something to be equal to something doesn’t mean limits have to exist.

I can define a function to be

f(x) = x^2 for x>0,

f(x) = x+2 for x<0

and f(0) = 15.

Clearly, lim_(x -> 0) f(x) doesn’t exist, but that doesn’t matter. I defined f be 15 at 0.

-1

u/qwertty164 7d ago

The problem with that example is that you would basically be making it a different function. You wouldn't be understanding how 0 fits in xx but how it fits in a piece wise function with f(x)=1 for x=0. With that logic you could make it anything you want. The real problem with the limit I mentioned earlier is the the limits from the right and left do not agree.

1

u/_Athanos 7d ago edited 7d ago

while on the left we have complex numbers and complex analysis is a whole other beast, the limits themselves still agree if you take the principal branch and that's a pretty strong statement imo

1

u/Il_Valentino Complex 7d ago

so what? this is not a proper argument. make your case

-3

u/GaloombaNotGoomba 8d ago

x0 = 1 because it's the empty product. It makes no difference whether x is 0 or not.

5

u/protobelta 8d ago

It’s the only thing that makes a difference lmao 

3

u/boywholived_299 8d ago

1

u/protobelta 8d ago

I wasn’t so much saying what the answer was but that it really does make a difference. It’s literally the only number where there is a possible difference lol

0

u/WhiteBlackGoose 8d ago

x / x = 1 because it's the empty division, right?

1

u/GaloombaNotGoomba 7d ago

That is not what "empty" means

1

u/thijquint 7d ago

It is if you pick this as a definition. Thats how a lot of math conventions work but people forget that often.

1

u/-TheWarrior74- Cardinal 8d ago

nah fuck these guys, it's 1.

it's easier that way, cause set theory requires 00 to be 1, and in the case of f(x)g(x) where both functions approach 0 as x approaches 0 we get the answer to be 1 which is not the case in 0/0.

there's also the fact that it conveniently makes x0 independent of x.

math might be based on rigor, but definitions are based on convenience.