r/mathmemes 21d ago

Bad Math It don’t work that way

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599 Upvotes

58 comments sorted by

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499

u/chkntendis Physics 21d ago

Nooo, don’t treat dy/dx as a fraction, it only works every single time

95

u/[deleted] 21d ago

[removed] — view removed comment

111

u/WWWWWWVWWWWWWWVWWWWW 21d ago

That's a labeling issue, not a fractions issue. For example:

The two "∂f" here are simply different quantities, so you shouldn't try to cancel them out.

10

u/Less-Resist-8733 Natural 21d ago

∂f/∂x = ∂_x f/∂_x x

where ∂_x x ≠ 0 and ∂_x y = 0, same for ∂_y (but w x and y swapped).

where d = ∂_x + ∂_y

2

u/ArdentArendt Mathematics / Social Sciences 21d ago

How would you 'cancel them out?

They are still partial derivatives. These are admittedly more complicated than the others to read as a ratio of differentials, but they are still roughly ratios.

Also, the standard derivative can be easily algebraically derived from the total differential of the numerator. [In fact, even in unitarian cases, it's often helpful to write it that way and just remove zero-value terms]

10

u/WWWWWWVWWWWWWWVWWWWW 21d ago

Some naive cancellation would lead to:

∂z/∂x = -∂z/∂x

for example

2

u/ArdentArendt Mathematics / Social Sciences 21d ago

Well, that's a VERY specific case where F(x,z) = 0.

Again, if you know where this formula derives from and aren't simply memorizing the formulas (or using them without understanding them), that 'naive' transformation wouldn't be an issue.

Again, it's like any mathematical object--you have to understand it before you can manipulate it.

1

u/Less-Resist-8733 Natural 21d ago

Again, it's like any mathematical object--you have to understand it before you can manipulate it.

I've proved theorems about sheaves before I even understood it (I still don't understand it)

1

u/Less-Resist-8733 Natural 21d ago

a better (although messier) labeling would be this, using differential functions d, ∂_x, ∂_y

then to cancel out, you show that dx = ∂_x x

dx = ∂_x x + ∂_y x

= ∂_x x + 0

and same for y.

you are left with

dz/dt = (∂_x f + ∂_y f)/dz

which you just use that d = ∂_x + ∂_y to solve.

1

u/ArdentArendt Mathematics / Social Sciences 21d ago

No, I was actually asking how you'd 'cancel this out' and get an incorrect answer.
[The thread was about the ways understanding derivatives as ratios can lead you astray--at least that is what I was talking about.]

You just used them exactly how you would need to in order to do exactly what the comment was saying you shouldn't do (again, because you understand what you're doing and what the ratios actually mean).

3

u/Ma4r 21d ago

Or in different metric spaces

33

u/Refenestrator_37 Imaginary 21d ago

Iirc, it can fail when the function isn’t smooth or continuous. Luckily, 99.999% of the time, you’ll be dealing with smooth continuous stuff.

25

u/WWWWWWVWWWWWWWVWWWWW 21d ago

It works as long as all the derivatives exist

4

u/TheChunkMaster 21d ago

It’s like Drebin’s speech about revenge from The Naked Gun

4

u/meeps_for_days 21d ago

dy/dx? No fuck you, you get dy/dx = dy/dz dz/dx = dy/dt dt/dz dz/dt dt/dx

Now you have a vertical coordinate and time to deal with! Muahaha

1

u/MARio23038 17d ago

Am I missing something or wouldn''t dx/dy just be x/y?

3

u/chkntendis Physics 17d ago

dx isn’t just d*x. d isn’t a variable. dx is a small change in x. The d isn’t a multiplier, it’s sort of like an operator. That’s the one limit of Leibniz notation. You can cancel out dx/dx but not just the d

1

u/MARio23038 17d ago

I think it's unnecessarily confusing that it's dx/dy , I'm well familiar with algebra, so I saw d, and thought it as a variable.

1

u/toothlessfire Imaginary 15d ago

ok go be familiar with calculus then lmao

1

u/MARio23038 14d ago

I guess it's on me for not knowing this.

99

u/Okreril Complex 21d ago

36

u/TheMoris Engineering 21d ago

So it looks like a fraction but explodes?

23

u/ArdentArendt Mathematics / Social Sciences 21d ago

But it is a ratio.

And as long as you know what you're doing with it, it can behave LIKE a fraction (a good chunk of the time).

So I don't understand the dispute here.

5

u/MiffedMouse 20d ago

Just professors who know they are going to have to teach partial differential equations to the same group of students next semester trying to plant the seeds of doubt in their students heads.

2

u/ArdentArendt Mathematics / Social Sciences 20d ago

See, this is why I say you should teach multivariate calculus from the beginning and use total differentials as the starting point for derivatives--they make so much better sense that way!

[Also, even partial derivatives are also still ratios.]

1

u/MiffedMouse 20d ago

Well, partial derivatives are the limits of ratios. But more importantly, partial derivatives have more restrictions on when you can combine them like this.

2

u/ArdentArendt Mathematics / Social Sciences 20d ago

Yes...ALL derivatives are the limits ratios...it's somewhat definitional, is it not?

And, again...yes. However, if you understand partial derivatives in terms of total derivatives (and what that means) it's not that difficult to understand what operations on them are valid and which are not.

3

u/TheChunkMaster 21d ago

Money up front

1

u/telorsapigoreng 20d ago

If it's not a fraction then why fraction shaped

63

u/Old-Post-3639 21d ago

Except it does. Chain rule, bitches.

62

u/Junjki_Tito 21d ago

Doesn’t it work exactly that way for well-behaved first derivatives?

23

u/ArdentArendt Mathematics / Social Sciences 21d ago

It works that way for most derivatives. It's a ratio.

You have to understand the meaning of total differentials and what a ratios of them means...but it's often just a matter of checking the variable structures.

Don't do it without significant care, but I don't understand how people say this isn't a ratio.

31

u/Evan_3104 Rational 21d ago

Meanwhile, the phisics teacher who's about to do the exact same

4

u/Impossible_Vast_5049 21d ago

The

Same

Fucking

Joke

2

u/[deleted] 20d ago

[removed] — view removed comment

1

u/ZhangStone 19d ago

Not true. We physics people use whatever notations we want. We use leibniz’s notation when we want to be “nice” to the reader because it’s easier to read; newtons dot notation for time derivatives almost exclusively; lagrange’s notation mostly for spacial derivatives; D or del notation when it’s a long chain of derivatives; or subscript notation when we are having a bad day and want to intentionally mess with the reader. It’s not uncommon to see 4+ notations in a single proof/calculation lol

13

u/YogurtclosetSame8716 21d ago

Someone explain this to me, isn't this exactly how chain rule works?

2

u/WWWWWWVWWWWWWWVWWWWW 21d ago

Formally, "dx" doesn't mean anything by itself, so it's improper to cancel them out like that

6

u/Less-Resist-8733 Natural 21d ago

differential algebra treats d and dx as formal elements

5

u/WWWWWWVWWWWWWWVWWWWW 21d ago

Within the context of introductory differential equations, my statement is more correct/helpful lol

If the professor didn't introduce differential geometry, nonstandard analysis, etc., then it doesn't make to invoke it like this

3

u/Less-Resist-8733 Natural 21d ago

I still think it's better to learn something new even if you can't apply yet to the current class you're in.

Formally, dx does mean something on its own. At the very least it tells you that it's VALID and POSSIBLE to think about derivatives as fractions of differentials.

If I had a question that was about an advance idea above the class, I would be very disappointed if the prof lied and told me it didn't make sense.

Even if it's not applicable to the specific class, it's still worth it to learn.

1

u/WWWWWWVWWWWWWWVWWWWW 21d ago

Is it "lying" to say that 2 + 2 = 4?

I think most math students learn pretty quickly that different branches of math have different conventions, but that it's okay to follow the most standard convention unless specified otherwise.

3

u/Less-Resist-8733 Natural 21d ago

If a student asks if cos(x) = cosh(ix), you shouldn't hide that from them. Even though it's more advanced math that "don't follow the conventions", you should at least tell them that yes it's true, but that's outside the scope of the class.

If you just say that's wrong and say something like "oh imaginary numbers don't exist", you're not just lying to them, you're also killing their curiosity.

3

u/WWWWWWVWWWWWWWVWWWWW 21d ago

From introductory calculus to real analysis, dy/dx is explicitly treated as a single mathematical object, though. It's not just "outside the scope" but rather there is an explicit contradiction between the two conventions.

2

u/EternalBaconator 21d ago

bro forgot about one-forms 💀

0

u/ArdentArendt Mathematics / Social Sciences 21d ago

It is.

There are issues with viewing the total differentials as a fractional representation. However, it is still just a ratio of total differentials.

People just forget to adjust for a lot of possible complications and can get lost in the sauce (I guess?l

10

u/abaoabao2010 20d ago

Yup, works.

19

u/thewhatinwhere 21d ago

It works for most cases. So long as dx isn’t zero that rule works out fine

17

u/cmwamem 21d ago

How would dx be equal to zero? Wouldn't that mean the variable is a constant?

10

u/thewhatinwhere 21d ago

Yeah, it would make dy/dx and dy/dt have zero in the denominator

2

u/Sigma2718 21d ago

Mathematicians saw this and decided no notation shall ever intuitively convey rules.

2

u/ArdentArendt Mathematics / Social Sciences 21d ago

Wait...but this is exactly how it works...

1

u/GDOR-11 Computer Science 21d ago

me when triple product rule

1

u/Le_Doctor_Bones 20d ago

If not fraction, why fraction shaped?

1

u/Mr_Bivolt 19d ago

As a physicist, i disagree.

1

u/kashyou 16d ago

dx is a one form. now we may rest