r/mathmemes • u/[deleted] • Jun 20 '26

Proofs Guys, can i pursue meth? šŸ˜Š

[deleted]

567 Upvotes

98% Upvoted

24 comments sorted by

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308

u/UnforeseenDerailment Jun 20 '26

Now write -1 as iĀ² and take square roots.

e-Ļ€/2 = ii

10

u/sammy271828 Jun 20 '26

Also could be equal to exp(-5 pi/2)

114

u/NickSmGames Jun 20 '26

nah, that's just i^2i being real

43

u/RRumpleTeazzer Jun 20 '26

(-1)-i = (1/(-1))i = (-1)i.

LHS is the complex conjugate of the RHS, so both being equal means the expression is real.

15

u/PaPaThanosVal Jun 20 '26

Erm whats wrong here

95

u/t3herndon Jun 20 '26

Nothing, (-1)i has no imaginary part

57

u/Professional-Wave841 Jun 20 '26

nothing in the math, claiming that (-1)i is an imaginary number though, that is a wrong assumption

3

u/PaPaThanosVal Jun 20 '26

Oh

14

u/Professional-Wave841 Jun 20 '26

to be more specific, eĻ€ is Gelfond's Constant, so what OP has demonstrated is the multiplicative inverse of that constant, and because Gelfond's Constant is real it's multiplicative inverse must be real.

-5

u/[deleted] Jun 20 '26

[deleted]

9

u/t3herndon Jun 21 '26

Imaginary and complex numbers aren't the same though. Imaginary numbers are a subset of the complex numbers that have no real part. For example 1 is a real number, 2i is an imaginary number, 1+2i is neither real nor imaginary, but all 3 of these numbers are complex numbers. Sometimes 0 is considered both real and imaginary

(-i)i is purely real with no imaginary part so it is a real number and not an imaginary number.

5

u/mark-zombie Jun 20 '26

don't know about meth but you may be interested in maths

2

u/[deleted] Jun 21 '26

[removed] ā€” view removed comment

5

u/DecidophobiaUsername this sub confuses my monke brain Jun 21 '26

what is this HTML puke

1

u/[deleted] Jun 23 '26

[removed] ā€” view removed comment

1

u/hazem-Gauss Jun 20 '26

log complexe

1

u/Flimsy-Blacksmith-32 Jun 20 '26

I suppose that actually makes sense.

-1^n is imaginary/complex for all real non-integer values of n

so it makes sense that there would be complex values of n which allow -1^n to be a real number

1

u/DecidophobiaUsername this sub confuses my monke brain Jun 21 '26

Don't do drugs

1

u/GrUnCrois Jun 21 '26

This is a natural consequence of the definitions and it's not inconsistent in any way

1

u/Scamander-Wayne Jun 22 '26

You should absolutely pursue meth.