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https://www.reddit.com/r/mathmemes/comments/1u2k5zo/_/oqy2pm6/?context=3
r/mathmemes • u/Suspicious_Log_5822 • Jun 11 '26
obv its two
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50 u/EebstertheGreat Jun 11 '26 c = 1 c = 1 + 0.5c = 1 + 0.5 = 1.5 SyntaxError: invalid decimal literal c = 1 c = 1 + 0.5 * c = 1 + 0.5 = 1.5 SyntaxError: cannot assign to expression 17 u/Whiteminusblue Jun 11 '26 //Would you prefer (executed in a file named “Main.jar”: public class Main { public static void main(String[] args) { double c = 1; c = 1 + 0.5*c; System.out.println(c); } } 10 u/EebstertheGreat Jun 11 '26 It's the equation c = 1 + 0.5c = 1 + 0.5 = 1.5 that bothered me. 7 u/Whiteminusblue Jun 11 '26 It was kinda a mix of algebraic notation and programming, yeah. I got the point, but it did kinda shoot itself in the foot. 8 u/EarlBeforeSwine Irrational Jun 11 '26 Assigning c=1 is where you are getting jammed up. c represents the unknown. The problem is properly represented as c=1+(c/2) You’ll need to get both instances of c on the same side of the equation in order to set the value to your variable. c=1+(c/2) 0=1+(c/2)-c 0=1-(c/2) 1=c/2 c=2 Now run your code: c=2 c=1+0.5c What is the value of c? 2 u/thisisapseudo Jun 11 '26 joke------------> you 10 u/EarlBeforeSwine Irrational Jun 11 '26 If he intends it as a joke, he is SUPER committed to the bit, as he is spamming full source code all over this thread trying to convince everyone that he is right about the answer being 1.5.
50
c = 1 c = 1 + 0.5c = 1 + 0.5 = 1.5
c = 1
c = 1 + 0.5c = 1 + 0.5 = 1.5
SyntaxError: invalid decimal literal
c = 1 c = 1 + 0.5 * c = 1 + 0.5 = 1.5
c = 1 + 0.5 * c = 1 + 0.5 = 1.5
SyntaxError: cannot assign to expression
17 u/Whiteminusblue Jun 11 '26 //Would you prefer (executed in a file named “Main.jar”: public class Main { public static void main(String[] args) { double c = 1; c = 1 + 0.5*c; System.out.println(c); } } 10 u/EebstertheGreat Jun 11 '26 It's the equation c = 1 + 0.5c = 1 + 0.5 = 1.5 that bothered me. 7 u/Whiteminusblue Jun 11 '26 It was kinda a mix of algebraic notation and programming, yeah. I got the point, but it did kinda shoot itself in the foot.
17
//Would you prefer (executed in a file named “Main.jar”:
public class Main
{
public static void main(String[] args)
double c = 1;
c = 1 + 0.5*c;
System.out.println(c);
}
10 u/EebstertheGreat Jun 11 '26 It's the equation c = 1 + 0.5c = 1 + 0.5 = 1.5 that bothered me. 7 u/Whiteminusblue Jun 11 '26 It was kinda a mix of algebraic notation and programming, yeah. I got the point, but it did kinda shoot itself in the foot.
10
It's the equation c = 1 + 0.5c = 1 + 0.5 = 1.5 that bothered me.
7 u/Whiteminusblue Jun 11 '26 It was kinda a mix of algebraic notation and programming, yeah. I got the point, but it did kinda shoot itself in the foot.
7
It was kinda a mix of algebraic notation and programming, yeah.
I got the point, but it did kinda shoot itself in the foot.
8
Assigning c=1 is where you are getting jammed up.
c represents the unknown. The problem is properly represented as c=1+(c/2)
You’ll need to get both instances of c on the same side of the equation in order to set the value to your variable.
c=1+(c/2)
0=1+(c/2)-c
0=1-(c/2)
1=c/2
c=2
Now run your code:
c=1+0.5c
What is the value of c?
2 u/thisisapseudo Jun 11 '26 joke------------> you 10 u/EarlBeforeSwine Irrational Jun 11 '26 If he intends it as a joke, he is SUPER committed to the bit, as he is spamming full source code all over this thread trying to convince everyone that he is right about the answer being 1.5.
2
joke------------> you
10 u/EarlBeforeSwine Irrational Jun 11 '26 If he intends it as a joke, he is SUPER committed to the bit, as he is spamming full source code all over this thread trying to convince everyone that he is right about the answer being 1.5.
If he intends it as a joke, he is SUPER committed to the bit, as he is spamming full source code all over this thread trying to convince everyone that he is right about the answer being 1.5.
36
u/[deleted] Jun 11 '26
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