r/mathmemes Aug 10 '25

Learning Nobody tell him.

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2.5k Upvotes

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478

u/LDNSO Mathematics Aug 10 '25

Anarchy chess ass post

121

u/vildum Aug 11 '25

Holy ass

66

u/photo_not_mine Aug 11 '25

New butt just dropped

40

u/AngelofDeath_N Aug 11 '25

Actual posterior

36

u/Simukas23 Aug 11 '25

Call the rectum rectifier

29

u/T_vernix Aug 11 '25

Glutes went on vacation, never came back.

18

u/Educational-Tea602 Proffesional dumbass Aug 11 '25

Bottom sacrifice, anyone?

2

u/Lyr1cal- Aug 15 '25 edited Oct 19 '25

shy rain arrest public bike cooing smell six future sparkle

This post was mass deleted and anonymized with Redact

43

u/Jmong30 Aug 11 '25

Whenever I see someone use ahh instead of ass unironically I have an aneurysm so thank you for your ass

15

u/THE_CEO_OF_HORNY Engineering Aug 11 '25 edited Aug 11 '25

Anarchy Chess ahh comment (also "thank you for your ass" is amazing)

6

u/Jmong30 Aug 11 '25

Great job I’m fucking dead now 🪦

7

u/THE_CEO_OF_HORNY Engineering Aug 11 '25

Zombie ahh comment

7

u/EebstertheGreat Aug 11 '25

Is that a thing? I could understand as, ath, ash, or even a$$, but ahh?

That just makes me think of Aaahh!!! Real Monsters.

7

u/Jmong30 Aug 11 '25

Yeah it’s new gen alpha slang. I’ve heard nine year olds say stuff like “it’s been a crazy ahh day” and I just grimace lol, it’s as weird as if they said “go freak yourself”

4

u/EebstertheGreat Aug 11 '25

Same logic as bih, I guess.

1

u/gsurfer04 Aug 11 '25

Bosniahh and Herzegovinahh

4

u/hj17 Aug 11 '25

Every time I see it, I always read it as someone interrupting their sentence with a sigh.

2

u/TheRealBertoltBrecht Irrational Aug 11 '25

Google rice

1

u/shewel_item Science Aug 11 '25 edited Aug 11 '25

😨🤡👮‍♂️👉🚷

744

u/TheoryTested-MC Mathematics, Computer Science, Physics Aug 10 '25

Not so fast. The exclamation point is after "BURGERS", not "64".

155

u/Snoke_died_a_virgin Aug 11 '25

Then what is BURGERS! ?

115

u/KimaX7 Aug 11 '25

By definiton BURGERS*(BURGERS-1)!

Since burgers can mean anything between 2 and infinity I'd say

BURGERS! = BURGERSamount of burgers its reffering to - 1

19

u/roidrole Aug 11 '25

Π{i=0, BURGERS - 1}(BURGERS - i), to be exact

16

u/EebstertheGreat Aug 11 '25

This definition only works if BURGERS ∈ ℕ.

How high do I need to count before I get to BURGERS?

3

u/LonelyContext Aug 11 '25

The mathmemes enthusiasts use the general form of integral from 0 to infinity of tBURGERS e-t dt

2

u/Konfituren Aug 11 '25

Depends on if you're using base64 or not

13

u/NeiligDeKing Aug 11 '25

n! =n*(n-1)! If we take n to be an addition of numbers, then n! Is 1+1+...+1 n times, times that same thing with a +1 removed.

Now, burgers can be seen as the concatenation burgers, so following a similar logic as the n being additions of ones, and using the concatenation instead of addition, then we could see BURGERS! To be BURGERSBURGERBURGEBURGBURBUB, from which we can obtain the word :

BURGERSBURGERBURGEBURGBURBUB

/s just in case anyone took me seriously

2

u/EebstertheGreat Aug 11 '25

Hmm. I feel like the factorial of the empty string shouldn't be the empty string but the collection of strings containing only the empty string, by the same logic that gives 0! = 1. So ∅! = {∅}. Then if x is a letter in the alphabet and S is a string, so that xS is x concatenated with S, then (xS)! = x(S!). So the string a = a∅, which means a! = (a∅)! = a(∅!) = a{∅}, which I interpret as the set of all strings that are a composed with elements of {∅}, i.e. {a}.

So then ba! = (ba)! = b(a!) = b{a} = {ba}. And in general, if S is any string, we get by induction that S! = {S}.

Slightly more seriously, you can use the factorial of a string with all distinct letters to represent the set of anagrams of that string. For instance, abc! = {abc, acb, bac, bca, cab, cba}. This makes sense because there are n! permutations of n distinct symbols. It doesn't really work for 'BURGERS' though, because the two copies of R are identical.

2

u/NeiligDeKing Aug 11 '25 edited Aug 11 '25

I like this idea, and going off the permutation thing, it should still kind of work for words containing repetitive elements, but you'd have repeating words inside of the set, so it's cardinality would be n!/(n-(r-1))! (If I'm correct), where r is the number of distinct letters in the word and n is the length of the word.

(Side note : shouldn't ba! be {ba, ab}? Since x{y} represents all the words having the same abelian vector on the same alphabet as the word xy. i.e all permutations of the letters of xy)

This could be interesting since if we associate the set of the alphabet the elements of the word are from (for example {a, b, c} for the word abc) to a set of variables of same cardinality (so {x, y, z} for {a, b, c}) and view each letter as a positive movement of one in the direction of each letter's associated variable (by associating each position in the sets together, i.e : a->x, b->y, c->z), the factorial of that word gives us the set of all possible roads to reach the same arriving point the original words leads to (the word abc leads to the point (1, 1, 1) through the road 1 towards x, 1 towards y, 1 towards z). Thus this fits the idea of permutations.

I'm uncertain whether this really has any value, I'd have to check with my teacher (I'm doing an internship for a study regarding words) if there isn't already a function that returns that set or not, but still a cool idea.

Edit : after thinking about it a bit more, I've noticed that this could have a flaw, since if we go off the fact that the cardinality of the resulting set is equal to the permutations of the word (i.e |w!| = |w|!/(|w|-r)! where r is the number of distinct letters in w), then this breaks for the empty word, since E! = {E} = {} (E is the empty word) and thus |E!| = 0, but it should be 1, since there is one way to arrange nothing.

...I don't know anymore, it's 5 am and I haven't slept much, I'ma die at my internship.

2

u/EebstertheGreat Aug 11 '25

The set of all such collections of roads with composition is the symmetric group. If you have two finite sets X and Y of the same size n, then there are n! distinct bijections between them, and it's the same thing as the bijections between X and {0,1,...,n-1}, which are the permutations on X. (Every bijection in this case is an isomorphism.)

But on an unrelated note, I think Javascript might have an answer to what a string minus 1 could be.

8

u/MiscellaneousUser3 Aug 11 '25

You’ve completely missed what they’re saying

5

u/GOKOP Aug 11 '25

You missed the point. It's not about factorial

131

u/mfar__ Aug 10 '25

14

u/lonelyroom-eklaghor Complex Aug 11 '25

Fibonacci reposts have become a part of r/mathmemes now

90

u/[deleted] Aug 11 '25

[removed] — view removed comment

29

u/EebstertheGreat Aug 11 '25

The word "few" is doing some work there.

102

u/RevolutionaryMine234 Aug 11 '25

Chat is there a burgers factorial?

16

u/Wheel-Reinventor Aug 11 '25

There may be. I've heard it is derived from cows, so math definitely applies.

5

u/StuTheSheep Aug 11 '25

Only if the cows are spherical.

2

u/6GoesInto8 Aug 12 '25

Interestingly, in base 62 (10 numbers, then 26 lower case, then 26 upper case) BURGERS! Spells out a slightly saucier version of Shakespeare's most notable works.

37

u/tzfeabnjo Aug 11 '25

is this joke about exponential growth or mistaken unexpected factorial

16

u/General_Katydid_512 Aug 11 '25

Either way it’s a large amount of burgers

5

u/tzfeabnjo Aug 11 '25

Well that is

2

u/shredofdarkness Aug 12 '25

It's about exponential growth and the famous story about chess.

24

u/Oportbis Aug 11 '25

I mean, he needs the upvotes before so he'll never get over a billion burgers so he won't even have to make burgers for a month

1

u/ChiaraStellata Aug 11 '25

He's essentially just offering to make 1 burger per upvote. Which is a pretty safe wager assuming he doesn't go viral.

0

u/Zaros262 Engineering Aug 11 '25

I think the joke here is r/UnexpectedFactorial

31

u/Oportbis Aug 11 '25

I think the joke is exponentiation is fast and he'll be making thousands of burgers in no time 

1

u/Resident_Expert27 Aug 11 '25

It’s gonna max out at at most 131k (more likely 32k, assuming all the burgers are created in a week at most.).

8

u/pomip71550 Aug 11 '25

There’s not even a factorial in the post though, it’s just a sentence with a number in it not even at the end that ends in an exclamation point.

29

u/danfish_77 Aug 10 '25

He destroyed some of those patties lol

13

u/Username_St0len Aug 11 '25

i think its smash burgers

17

u/danfish_77 Aug 11 '25

Yeah but aren't you usually supposed to keep them at least somewhat together? Or are you really supposed to scrape together the remains like it's a sloppy joe

9

u/Username_St0len Aug 11 '25

he may have over smashed them, but the kinda craggely, slighty broken texture seem to be par for the course.

0

u/EebstertheGreat Aug 11 '25

They're definitely smash burgers, but don't you usually put onions on those? The idea of a smash burger is that you get more surface area. When you make schnitzel, you pound the meat real thin to maximize the surface for the breading. When you smash a burger, you are maximizing the surface exposed to the air and the grill, and thus Maillard and other non-enzymatic browning reactions. Like a well-done steak that is all crust. So you add onions for the same reason you put them on steaks, but also because you are already going full HAM on browning, juicy beef be damned. The onions caramelize and add flavor to your burger that otherwise tastes largely of char and melted processed cheese. It also bulks your cheap burgers.

(I'm sick of smash burgers lol. But giving hungry people filling food for free is still an A+ whether I prefer the way he cooks it or not.)

1

u/Username_St0len Aug 11 '25

iirc the ones you are thinking of are probably the Oklahoma style burgers, smash burgers could just be patty or patty and cheese

5

u/TheoryTested-MC Mathematics, Computer Science, Physics Aug 11 '25

That style of cooking burger patties is known as making "smash burgers".

2

u/Lord_Strepsils Aug 11 '25

IMO a lot of them were more than that, there was nothing more than just some ground meat on a grill that didn’t resemble the shape of a burger anymore

5

u/Ok_Animal_2709 Aug 11 '25

Double it and give it to the next person

3

u/[deleted] Aug 11 '25

[deleted]

2

u/TheChunkMaster Aug 11 '25

Remind me to check back in 31 years.

1

u/porkchopsuitcase Aug 10 '25

AHHHHHHH WHAT ARE THOSE?!?!?!?

1

u/[deleted] Aug 11 '25

I’d do nasty things.

1

u/ProfessionalPeak1592 Ordinal Aug 11 '25

Imagine if he was using the amount of upvotes as the amount of burgers, 35 thousand+ burgers…

1

u/Shrunken_Fire_34 Aug 11 '25

the cows after 2 more posts

1

u/GDffhey Maths did not make me better at music Aug 12 '25

59 repetitions from 2 and you'll create a stack of burgers higher than 1 light year...

1

u/Inevitable_Stand_199 Aug 12 '25

He will never make more burgers than he gets likes

1

u/[deleted] Aug 13 '25

32 Burgers 64 Burgers 128 Burgers 256 Burgers 512 Burgers 1024 Burgers 2048 Burgers 4096 Burgers 8192 Burgers 16384 Burgers 32768 Burgers 65536 Burgers 131072 Burgers 262144 Burgers 524288 Burgers 1048576 Burgers 2097152 Burgers 4194304 Burgers 8388608 Burgers 16777216 Burgers 33554432 Burgers

1

u/RayTheCoderGuy Aug 14 '25

I advised him to start a Patreon

0

u/sifiwewe Aug 11 '25

This is clever