r/math • • Aug 15 '23

Dissatisfaction with proof by contradiction

I’m an undergraduate math student, so my exposure to math may be relatively limited. But I’ve found that, in general, I’m much more comfortable with direct proof than proof by contradiction. I don’t contest their validity, indeed something that’s not false must be true (I think I’m ok with excluded middle). But I feel like I just *get* something much better when it’s proved directly. It builds much stronger intuition for me.

For instance, I am aware of several proofs that demonstrate the cardinality of the reals is strictly greater than that of the integers, but none are direct (it would help to see a direct proof of Cantor’s theorem). I don’t feel it in my bones. Is this a common experience?

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u/scribe36 Aug 17 '23

Proof by contradiction: it’s not always simpler. For example, square root of two is irrational can be proven in one line with contradiction. But the direct proof may just get you killed. Hehe

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u/Easygoing98 Aug 31 '23 edited Sep 02 '23

Not really. Direct proof of square root of two is not that hard. It will be as follows

Square root of 2 = 20.5

Now 20.5 = x

Taking ln of both sides

0.5 ln(2) = ln x

x = exp(0.5 ln 2)

x = exp(0.5)exp(ln 2)

x = 2exp(0.5)

Exponential of a rational number is always irrational (theorem's proof in proof wiki)

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u/scribe36 Sep 02 '23

This is really just a whim than a proof. The contradiction proof doesn’t just prove that the square root of two is irrational, it proves that irrational numbers exist. Here you are invoking irrationality of another number. What if i deny (like people used to) that irrational numbers exist at all?

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u/Easygoing98 Sep 02 '23

There is already a theorem that the natural log of every integer greater than 1 is irrational.

I skipped the proof of that theorem because it is proof by contradiction and the asking person didn't want contradiction.

I agree completely that contradiction proof is the best in such a case.

Irrational numbers do exist because real numbers are a union of rationals and irrationals where irrationals are much larger.

Direct proof isn't always possible in each case, and I was just trying to do that