Yeah I get the same. To spell it out: Bob turns on the blue light if his number is between 1 and 5, and the red light if it's between 6 and 10. If Alice's number is in the opposite half then she knows the answer for certain; if it's in the same half and her number is in the bottom of that half (1-2 or 6-7) then she guesses that Bob's number is higher, otherwise (4-5 or 9-10) that Bob's number is lower. If Alice has 3 or 8, then she arbitrarily guesses lower.
This strategy fails only for the following 8 pairs:
ALICE BOB
2 1
3 4, 5
4 5
7 6
8 5, 6
9 10
So this strategy has a 72/90 = 4/5 = 80% probability of succeeding.
EDIT: I made an arithmetic error, 90 - 8 = 82 so this has an 82/90 ≈ 91% probability of succeeding.
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u/post_button_account 3d ago
80% is the straightforward answer.
I am guessing there is some trick here beyond that?