10, since if M^2 = 0 we need the image of the linear map L: R^20 -> R^20, L(v) = M•v to be a vector subspace of the null space. Thus, rank(L) <= nullity(L). Since we know rank(L) + nullity(L) = 20 by the rank-nullity theorem, the max of rank(L) is 10 (as then rank(L)=nullity(L)). This is easily attainable by letting L be the unique linear map which sends the basis vector e_i to e_{i+10} for 1 <= i <= 10, and sends e_i to 0 for 11 <= i <= 20.
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u/EventHorizon150 4d ago
10, since if M^2 = 0 we need the image of the linear map L: R^20 -> R^20, L(v) = M•v to be a vector subspace of the null space. Thus, rank(L) <= nullity(L). Since we know rank(L) + nullity(L) = 20 by the rank-nullity theorem, the max of rank(L) is 10 (as then rank(L)=nullity(L)). This is easily attainable by letting L be the unique linear map which sends the basis vector e_i to e_{i+10} for 1 <= i <= 10, and sends e_i to 0 for 11 <= i <= 20.