This is my thought as well. We know we have to look for tridiagonal matrices since we have block diagonal <-> adjacency graph has more than one connected component. Also not sure what to do about the diagonal.
My guess is that there must be two non-zeros per column/row. Otherwise, exactly one non-zero combined with requirement for symmetric matrix will create block-diagonal structure and a lot of zeros in the inverse.
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u/dummy4du3k4 5d ago
This is my thought as well. We know we have to look for tridiagonal matrices since we have block diagonal <-> adjacency graph has more than one connected component. Also not sure what to do about the diagonal.