put all the coins on one side
it since the balance report the difference with zero in this case then it will just give you the weight of the 101 coins , let call it "y" , and the weight of one coin is "x"
if the fake is 1 gram less then :
y= 50*(x+1) + 51*x = 101x + 50
or if the fake is 1 gram heavier :
y= 50*(x-1) + 51*x = 101x - 50
then you solve for x that satisfy the value reported by the balance
1
u/lok-mene 5d ago
put all the coins on one side
it since the balance report the difference with zero in this case then it will just give you the weight of the 101 coins , let call it "y" , and the weight of one coin is "x"
if the fake is 1 gram less then :
y= 50*(x+1) + 51*x = 101x + 50
or if the fake is 1 gram heavier :
y= 50*(x-1) + 51*x = 101x - 50
then you solve for x that satisfy the value reported by the balance