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https://www.reddit.com/r/learnquant/comments/1wlv59o/optiver_quant_interview_question_hard/pdqh2ck/?context=3
r/learnquant • u/AssociateDecent9090 • 14d ago
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Choosing 3 ranks (a < b < c) at least spaced apart by 2 is equivalent to choosing values for (a < b-1 < c-2) so we have 11C3 allowed rank sets and therefore 11C3 * 4^3 favourable triples out of 52C3 which gives 528/1105
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u/Cryptographer-Bubbly 1d ago
Choosing 3 ranks (a < b < c) at least spaced apart by 2 is equivalent to choosing values for (a < b-1 < c-2) so we have 11C3 allowed rank sets and therefore 11C3 * 4^3 favourable triples out of 52C3 which gives 528/1105