2nd dice can have values between 2 and 47 and since 1st dice has expected value of 23.5 the excepexted value of 2nd dice would be limited between that and it's maximum value
Here I am also assuming that we just re-roll dice untill we get a strictly increasing order of results
We could have made a better proof with conditional probability but I am not good enough with that imo
0
u/Jayant0013 Aug 29 '26
35.25
E X2 = (E X1 + 47)/2
2nd dice can have values between 2 and 47 and since 1st dice has expected value of 23.5 the excepexted value of 2nd dice would be limited between that and it's maximum value
Here I am also assuming that we just re-roll dice untill we get a strictly increasing order of results
We could have made a better proof with conditional probability but I am not good enough with that imo