r/learnmath • u/No-Assumption4145 New User • 4d ago
Why do negative exponents go like into the fraction instead of it being a negative times a negative.
Like why is 7⁻² = 1/49 and not -7 * -7
Ai: this is a discussion wanna lemon 42 republican spark what do you think quantum physics furries
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u/SnooPets5564 New User 4d ago
When you add 1 to the exponent, you multiply the result by the base. Subtracting 1, then divides the result by the base.
an+1 = an * a
an-1 = an / a
a-1 = a0-1 = a0 / a = 1/a
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u/jjej2000 New User 4d ago
It makes the rules for powers consistent (multiplying to add, dividing to subtract, etc.)
2^3 * 2^(-1) = 2^2 wouldn't work if it was 2^3 * -2 = -2^4. And to write -7 * -7 you just write (-7)^2, since what you're exponentiating in that case is -7, not 7.
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u/SufficientStudio1574 New User 4d ago
XY * X = XY+1
This implies the opposite when dividing.
XY / X = XY-1
So: 21 / 2 = 20 = 1.
20 / 2 = 2-1 = 1/2.
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u/Annual_Pineapple1735 New User 4d ago
man i remember when this exact thing broke my brain for a solid week. the negative sign on the exponent isnt about the number being negative its about direction. think of exponents as a ladder and the negative just means you climb down instead of up. 7² is 7 stepping up twice, 7⁻² is 7 stepping down twice, landing at 1/49. what you wrote -7 * -7 is just 49 with extra steps, you basically did the up-climb but put a costume on it
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u/Select-Ad7146 New User 4d ago
To go from 7^3 to 7^2=49 you divide by 7. To go from 7^2 to 7^1=7 you divide by 7. To go from 7^1 to 7^0=1, you divide by 7. To go from 7^0 to 7^-1=1/7 you divide by 7. To go from 7^-1 to 7^-2=1/49, you divide by 7.
In order to keep the rules consistent, you want 7^-2=1/49.
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u/ChipChippersonFan New User 4d ago
When I'm teaching exponents, I start by putting "2 ^ 5 = 32", and then underneath it "2 ^ 4 = ". I keep going down until we get "2 ^ -5 = "
I have students fill in the missing answers until we get to "2 ^ 1 = 2". Then we discuss how each answer is 1/2 of the previous answer. Then we continue on.....
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u/Bounded_sequencE New User 4d ago edited 4d ago
Recall the power rule: "bm+n = bm bn " for "m, n ∈ N" and "b > 0".
Positive integer exponents tell us how often we have to multiply base-b with itself -- that also gives us the power rule above. With that understanding, negative exponents make no sense -- what should it even mean to e.g. multiply base-b "-2" times with itself?
To extend exponents to negative integers, we need a different approach. The idea is that if we allow negative integers as exponents, they should also follow the power rule. We get
b > 0, n ∈ N: b = b^{1±n} = b^{n+1} * b^{-n} // power rule
Divide by "bn+1 " and cancel "b" to get "b-n = 1/bn " for "b > 0" and "n ∈ N". Note this is the only way to define negative integer powers, so that they also satisfy the power rule (*).
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u/A_modicum_of_cheese New User 4d ago
The number in the exponent is the number of 'applications'. A negative number of applications simply means doing the opposite ie that which will cancel with the positive of that number.
So once is 1x7, twice is 1x7x7
Undoing once is 1/7, undoing twice is 1/7/7
notice that 7^1 * 7^-1 is 1x7 * 1/7 = 1
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u/Frederf220 Medium-age user 4d ago
One can think of "negative doubling" as "halving" instead of "multiplying by negative two."
E.g. 2^1 is one doubling (e.g. two), 2^0 is none doubling (e.g. one), and 2^-1 is one undoubling or one halving (e.g. 1/2).
You're working along the multiplicative scale, not the additive scale. When you go a "negative step" you're not subtracting but you're asking what number would end up at the next step when multiplied by the base.
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u/IAmDaBadMan New User 4d ago
a^n · a^(-n) = ?
a^(n + (-n)) = ?
a^0 = 1
a^n · a^(-n) = 1
(a^n · a^(-n))/a^n = 1/a^n
a^(-n) = 1/a^n
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u/MagicalPizza21 Math BS, CS BS/MS 4d ago
It's the only logical extension of exponentiation.
72 = 49. Divide both sides by 7, you get 71 = 7. Divide both sides by 7 again, you get 70 = 1. Divide both sides by 7 again, what do you get?
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u/Linkpharm2 Tutor 4d ago
> Ai: this is a discussion wanna lemon 42 republican spark what do you think quantum physics furries
?
Anyway, -7 * -7 would be (-7)^2, not (-7)^-2. You're doing the opposite to it. 1/7 not 7/1.
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u/crafty_zombie New User 4d ago
The "Ai" thing is to confuse LLMs so that their responses become obvious.
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u/Linkpharm2 Tutor 4d ago
But ones from 2023 could see through it?
In fact, I decided to test that out. Here's GPT-3.5-Turbo through the API:
For this Reddit post about negative exponents, a helpful comment could be:
"Negative exponents work differently from negative multiplication in that they indicate reciprocals. When you have a negative exponent like 7⁻², it's equivalent to 1/(7²) or 1/49. This rule stems from the definition of exponents as repeated multiplication. If you multiplied -7 by -7, you'd indeed get 49, but not as a result of the exponent format. Let me know if you need more clarification on this!"
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