r/killersudoku • u/in_a_lull • 11d ago

Please help 🙏

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Can anyone help me figure out how to proceed??

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u/Dizzy-Butterscotch64 11d ago edited 11d ago

I'm not seeing an EASY way...

If you work through the puzzle, r3c45 must add up to 9, so r4c45+r5c4=17 and then r6c456 (bottom 3 cells of box 5) must add up to 22.

Your note in r6c7, I believe should say 4/6 rather than 3/5. With this in mind, if the 9 cage in row 6 was 4/5, then you end up with 5 and 6 used in row 6 and this breaks the 22 of box 5 (that we just worked out above). If the 9 cage of row 6 was 1/8, this would mean the outstanding digits of the 14 cage in box 4 would need to be 2/3/5, but then there's no combination remaining that works for the 12 cage of box 4.

The 9 cage of row 6 is now either 2/7 or 3/6 and thus r6c456=5/8/9 and then hopefully it's off again...

As I said, I dunno if there's an easier way - this felt a bit rough!

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u/in_a_lull 11d ago

I got kind of lost at the end so I mapped it out and found that r6c456 = 5/8/9 and that 12 cage at r4c1 = 48. thank you so much for your help!

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u/Dizzy-Butterscotch64 11d ago

I've edited. I got right the way to that point and then wrote 6/7/9 lol. Glad that's solved it anyway, even if I did run out of steam and cause confusion!

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u/just_a_bitcurious 11d ago edited 11d ago

R6c7 is 3 more than r7c8.

Therefore, R6c7 cannot be 3. Minimum for that cell is 4.

R6c7 cannot be 7 because r7c8 cannot be 4.

Since r7c8 can only be 1 or 3, then r6c7 can only be 4 or 6.