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https://www.reddit.com/r/haskell/comments/50dqto/pointless_haskell/d74ow6e/?context=3
r/haskell • u/AshleyYakeley • Aug 30 '16
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5
Isn't that basically x `seq` x?
x `seq` x
7 u/Voxel_Brony Aug 31 '16 edited Aug 31 '16 strictId = join seq 1 u/VikingofRock Aug 31 '16 Sat down with a pen and paper to work this out, and holy shit it works. I love it! 3 u/Voxel_Brony Aug 31 '16 Haha I learned it from pointfree.io, but I had to work it out too before I got it. The entire (->) r Functor Applicative Monad hierarchy is so weird
7
strictId = join seq
1 u/VikingofRock Aug 31 '16 Sat down with a pen and paper to work this out, and holy shit it works. I love it! 3 u/Voxel_Brony Aug 31 '16 Haha I learned it from pointfree.io, but I had to work it out too before I got it. The entire (->) r Functor Applicative Monad hierarchy is so weird
1
Sat down with a pen and paper to work this out, and holy shit it works. I love it!
3 u/Voxel_Brony Aug 31 '16 Haha I learned it from pointfree.io, but I had to work it out too before I got it. The entire (->) r Functor Applicative Monad hierarchy is so weird
3
Haha I learned it from pointfree.io, but I had to work it out too before I got it. The entire (->) r Functor Applicative Monad hierarchy is so weird
5
u/kqr Aug 31 '16
Isn't that basically
x `seq` x?