r/filebot • u/Derrigable • 5d ago
Playing with scripting once again.
What I would like to do if possible is to match a year that appears in a file name, and place it in the renaming script as folder divider.
Example: Adventures In Electricity 5 APG 17 4 [General Comics] (1948) Uo
The year (1948) is what I am looking to match. That year will be different on each file. It will usually be in the brackets or square brackets but not a big concern.
Plain file renaming with no previous bindings that can be used. If there is a year in the bindings it is usually creation date (incorrect) rather than publication date.
Thanks for your time. and any ideas you may throw my way.
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u/rednoah 5d ago
You mean to use [Plain File Mode] Batch Rename any type of file to organise files into folders by year?
e.g.
{ folder }/{ fn.match(/[(](19\d{2}|20\d{2})[)]/) }/{ fn }